Find four consecutive integers who sum is 286

Find four consecutive integers who sum is 286

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1: x 2: x + 1 3: x + 2 4: x+ 3 4x + 6 = 286 4x = 280 x=70 plug it back in 1: 70 2: 70 +1 = 71 3: 70 +2 = 72 4: 70+ 3= 73

sorry about taking so long i almost forgot how to do it

Easiest way is to use symmetry, just divide by 4 and then the 4 numbers are the 2 sets of 2 integers on each side of that number.

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