Here's the question you clicked on:
justinee
1 = |g +3|
& what about; |y - 1| <_ 8
ok, when you have your absolute value alone on the other side of the equal sign, you can solve in two ways. You make what's NOT in the absolute value signs (which is 1 in this problem) opposites. So you would solve when 1 is positive and negative 1 = g+3 solve this, subtract 3 from both sides -2= g that's one solution now, make the 1 negative -1 = g + 3 subtract the 3 -4 = g so your two soulitons are g= -4 and g = -2
so for the second one, you already have what's in the absolute value signs alone, so you can start making what's on the other side of the equal sign opposites. so you have two solutions to this, you have to make 8 positive and negative y - 1 < 8 solve this y < 9 solve another one where the 8 is negative y - 1 < -8 y < -7
do you need help on understanding because i don't think i explained this very well