anonymous
  • anonymous
how do you graph this function?please show work! g(x)=5|x-4|+2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
There could be a little trick to this but I havent done one like this in a loong time. Start with g(x) = abs(x) You know what that graph looks like Then make the transformation to g(x) = abs(x - 4) and keep going until you got your whole function
across
  • across
That's the best way to do it, imho.
anonymous
  • anonymous
I'm sorry, can you explain it a little more thoroughly Walleye?

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across
  • across
Do you know what the graph of\[f(x)=|x|\]looks like?
anonymous
  • anonymous
yes i do
across
  • across
What would happen to that graph if we do this\[f(x)=|x-4|\]
anonymous
  • anonymous
it would move over 4 to the right, right?
anonymous
  • anonymous
Thanks Across, you seem to be very good in math :D
across
  • across
That's correct! Now, what would happen to it if we multiply it by five like this\[f(x)=5|x-4|\]
across
  • across
Aww thank you Walleye :)
anonymous
  • anonymous
I'm not really sure :( sry. i know that the graph is going to move up 2 tho, right?
across
  • across
It is almost the same thing as multiplying\[f(x)=x\]by 5\[f(x)=5x.\]The slope of the line gets "steeper." :)
anonymous
  • anonymous
If i may, think of the function f(x) = x and f(x) = 5x What happens when you mutiply f(x) = x by 5??
anonymous
  • anonymous
Copycat!
anonymous
  • anonymous
so then it does down 5?
anonymous
  • anonymous
*goes
across
  • across
No, the graph gets "steeper" like this (see attached).
1 Attachment
across
  • across
Finally, I'm sure you already knows what will happen to the graph if we add two to it\[f(x)=5|x-4|+2\]
across
  • across
know*
anonymous
  • anonymous
Try graphing all of these functions yourself and you will get a feel for how these transformations affect the function
anonymous
  • anonymous
I got it! Thank you guys so much :) I appreciate it!
anonymous
  • anonymous
No problem!!! Practicing problems like these can be a bore but soon enough you will get good enough to see most any function and know what it looks like right away!!
anonymous
  • anonymous
Lol! it's true, they are a bore :) thanks again!

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