## anonymous 4 years ago Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

1. anonymous

A. log3 B. 4 log3 C. log3 D. 4 log3 (k + m – n)

2. anonymous

Let's first recall a couple of log identities: $\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]$From the First identity:$\log(k^7) + \log(m^6) - \log(n^9)$From the Second and Third Identity$\log({k^7 m^6 \over n^9})$

3. anonymous

hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

4. anonymous

that is choice C, but it has 3with the log?

5. anonymous

Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.

6. anonymous

so are you master of the logarithms now?

7. anonymous

not totally..lol

8. anonymous

keep it up.. have fun

9. anonymous

lol..do you know a good website to graph functions?

10. anonymous
11. anonymous

What is the function? I'll type it in so you have an idea of how to type things in.

12. anonymous

13. anonymous

thanks eashmore for the physics help

14. anonymous

f(x) = log0.3 x

15. anonymous

A base of 0.3?

16. anonymous
17. anonymous

yes