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whatevs

  • 4 years ago

Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

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  1. whatevs
    • 4 years ago
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    A. log3 B. 4 log3 C. log3 D. 4 log3 (k + m – n)

  2. eashmore
    • 4 years ago
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    Let's first recall a couple of log identities: \[\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]\]From the First identity:\[\log(k^7) + \log(m^6) - \log(n^9)\]From the Second and Third Identity\[\log({k^7 m^6 \over n^9})\]

  3. do_0b.ie
    • 4 years ago
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    hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

  4. whatevs
    • 4 years ago
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    that is choice C, but it has 3with the log?

  5. eashmore
    • 4 years ago
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    Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.

  6. do_0b.ie
    • 4 years ago
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    so are you master of the logarithms now?

  7. whatevs
    • 4 years ago
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    not totally..lol

  8. do_0b.ie
    • 4 years ago
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    keep it up.. have fun

  9. whatevs
    • 4 years ago
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    lol..do you know a good website to graph functions?

  10. eashmore
    • 4 years ago
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    http://www.wolframalpha.com

  11. eashmore
    • 4 years ago
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    What is the function? I'll type it in so you have an idea of how to type things in.

  12. whatevs
    • 4 years ago
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    oh yeah...totally forgot about tht..thanks

  13. do_0b.ie
    • 4 years ago
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    thanks eashmore for the physics help

  14. whatevs
    • 4 years ago
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    f(x) = log0.3 x

  15. eashmore
    • 4 years ago
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    A base of 0.3?

  16. eashmore
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=plot+log_0.3%28x%29

  17. whatevs
    • 4 years ago
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    yes

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