## whatevs 3 years ago Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

1. whatevs

A. log3 B. 4 log3 C. log3 D. 4 log3 (k + m – n)

2. eashmore

Let's first recall a couple of log identities: $\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]$From the First identity:$\log(k^7) + \log(m^6) - \log(n^9)$From the Second and Third Identity$\log({k^7 m^6 \over n^9})$

3. do_0b.ie

hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

4. whatevs

that is choice C, but it has 3with the log?

5. eashmore

Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.

6. do_0b.ie

so are you master of the logarithms now?

7. whatevs

not totally..lol

8. do_0b.ie

keep it up.. have fun

9. whatevs

lol..do you know a good website to graph functions?

10. eashmore
11. eashmore

What is the function? I'll type it in so you have an idea of how to type things in.

12. whatevs

oh yeah...totally forgot about tht..thanks

13. do_0b.ie

thanks eashmore for the physics help

14. whatevs

f(x) = log0.3 x

15. eashmore

A base of 0.3?

16. eashmore
17. whatevs

yes

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