Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

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Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

Mathematics
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A. log3 B. 4 log3 C. log3 D. 4 log3 (k + m – n)
Let's first recall a couple of log identities: \[\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]\]From the First identity:\[\log(k^7) + \log(m^6) - \log(n^9)\]From the Second and Third Identity\[\log({k^7 m^6 \over n^9})\]
hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

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that is choice C, but it has 3with the log?
Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.
so are you master of the logarithms now?
not totally..lol
keep it up.. have fun
lol..do you know a good website to graph functions?
http://www.wolframalpha.com
What is the function? I'll type it in so you have an idea of how to type things in.
oh yeah...totally forgot about tht..thanks
thanks eashmore for the physics help
f(x) = log0.3 x
A base of 0.3?
http://www.wolframalpha.com/input/?i=plot+log_0.3%28x%29
yes

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