anonymous
  • anonymous
Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
A. log3 B. 4 log3 C. log3 D. 4 log3 (k + m – n)
anonymous
  • anonymous
Let's first recall a couple of log identities: \[\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]\]From the First identity:\[\log(k^7) + \log(m^6) - \log(n^9)\]From the Second and Third Identity\[\log({k^7 m^6 \over n^9})\]
anonymous
  • anonymous
hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

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anonymous
  • anonymous
that is choice C, but it has 3with the log?
anonymous
  • anonymous
Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.
anonymous
  • anonymous
so are you master of the logarithms now?
anonymous
  • anonymous
not totally..lol
anonymous
  • anonymous
keep it up.. have fun
anonymous
  • anonymous
lol..do you know a good website to graph functions?
anonymous
  • anonymous
http://www.wolframalpha.com
anonymous
  • anonymous
What is the function? I'll type it in so you have an idea of how to type things in.
anonymous
  • anonymous
oh yeah...totally forgot about tht..thanks
anonymous
  • anonymous
thanks eashmore for the physics help
anonymous
  • anonymous
f(x) = log0.3 x
anonymous
  • anonymous
A base of 0.3?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=plot+log_0.3%28x%29
anonymous
  • anonymous
yes

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