\[\log_{3} (\log_{2} x) + \log_{1/3} (\log_{1/2} y)]=1

\[\log_{3} (\log_{2} x) + \log_{1/3} (\log_{1/2} y)]=1

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\[\log_{3} (\log_{2} x) + \log_{1/3} (\log_{1/2} y)=1\]

ya ure rite !!!!!!!now pls solve!

you can't solve because you have two variables and one equation

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