## anonymous 4 years ago f'(x)=(2 ln(x))/x How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please.

1. anonymous

Do you want to solve the equation for x?

2. anonymous

Yes

3. across

That's not possible, unless you're setting f'(x)=0.

4. across

Are you trying to find maxima/minima?

5. across

$\frac{2\ln(x)}{x}=0$doesn't seem too bad.

6. anonymous

if you are looking for critical value , look for where function diverge too

7. anonymous

How do I proceed after this to find the value for x?

8. anonymous

Yes I am looking for critical values

9. anonymous

what happened if you plug in 0 for x

10. anonymous

you can't take the ln(0). There has to be some other way related to log rules to solve this question, and I can't figure it out.

11. anonymous

it diverges, which mean it is a criticle point. a critical point of a function of a real variable is any value in the domain where either the function is not differentiable or its derivative is 0

12. across

$\frac{2\ln(x)}{x}=0,$$2\ln(x)=0,$$\ln(x)=0,$$x=1.$