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 3 years ago
f'(x)=(2 ln(x))/x
How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please.
 3 years ago
f'(x)=(2 ln(x))/x How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please.

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Walleye
 3 years ago
Best ResponseYou've already chosen the best response.0Do you want to solve the equation for x?

across
 3 years ago
Best ResponseYou've already chosen the best response.1That's not possible, unless you're setting f'(x)=0.

across
 3 years ago
Best ResponseYou've already chosen the best response.1Are you trying to find maxima/minima?

across
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2\ln(x)}{x}=0\]doesn't seem too bad.

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0if you are looking for critical value , look for where function diverge too

ameni
 3 years ago
Best ResponseYou've already chosen the best response.0How do I proceed after this to find the value for x?

ameni
 3 years ago
Best ResponseYou've already chosen the best response.0Yes I am looking for critical values

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0what happened if you plug in 0 for x

ameni
 3 years ago
Best ResponseYou've already chosen the best response.0you can't take the ln(0). There has to be some other way related to log rules to solve this question, and I can't figure it out.

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0it diverges, which mean it is a criticle point. a critical point of a function of a real variable is any value in the domain where either the function is not differentiable or its derivative is 0

across
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2\ln(x)}{x}=0,\]\[2\ln(x)=0,\]\[\ln(x)=0,\]\[x=1.\]
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