## ameni Group Title f'(x)=(2 ln(x))/x How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please. 2 years ago 2 years ago

1. Walleye Group Title

Do you want to solve the equation for x?

2. ameni Group Title

Yes

3. across Group Title

That's not possible, unless you're setting f'(x)=0.

4. across Group Title

Are you trying to find maxima/minima?

5. across Group Title

$\frac{2\ln(x)}{x}=0$doesn't seem too bad.

6. imranmeah91 Group Title

if you are looking for critical value , look for where function diverge too

7. ameni Group Title

How do I proceed after this to find the value for x?

8. ameni Group Title

Yes I am looking for critical values

9. imranmeah91 Group Title

what happened if you plug in 0 for x

10. ameni Group Title

you can't take the ln(0). There has to be some other way related to log rules to solve this question, and I can't figure it out.

11. imranmeah91 Group Title

it diverges, which mean it is a criticle point. a critical point of a function of a real variable is any value in the domain where either the function is not differentiable or its derivative is 0

12. across Group Title

$\frac{2\ln(x)}{x}=0,$$2\ln(x)=0,$$\ln(x)=0,$$x=1.$