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ameni
f'(x)=(2 ln(x))/x How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please.
Do you want to solve the equation for x?
That's not possible, unless you're setting f'(x)=0.
Are you trying to find maxima/minima?
\[\frac{2\ln(x)}{x}=0\]doesn't seem too bad.
if you are looking for critical value , look for where function diverge too
How do I proceed after this to find the value for x?
Yes I am looking for critical values
what happened if you plug in 0 for x
you can't take the ln(0). There has to be some other way related to log rules to solve this question, and I can't figure it out.
it diverges, which mean it is a criticle point. a critical point of a function of a real variable is any value in the domain where either the function is not differentiable or its derivative is 0
\[\frac{2\ln(x)}{x}=0,\]\[2\ln(x)=0,\]\[\ln(x)=0,\]\[x=1.\]