anonymous
  • anonymous
Subract.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
-
anonymous
  • anonymous
\[\left(\begin{matrix}6x_2y \\ x^2+5xy-6y^2\end{matrix}\right)-\left(\begin{matrix}3x+2y \\ x^2+4xy-5y^2\end{matrix}\right)\]
anonymous
  • anonymous
do you know how to add and subtract vectors? \[\left(\begin{matrix}a \\ b\end{matrix}\right) + \left(\begin{matrix}c \\ d\end{matrix}\right) = \left(\begin{matrix}a+c \\ b+d\end{matrix}\right)\]

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anonymous
  • anonymous
No i do not?
across
  • across
He literally told you how to up there.
anonymous
  • anonymous
your a = 6x2y your c = 3x + 2y ... does this help at all?
anonymous
  • anonymous
Yes now i get it... and my bad across :/
anonymous
  • anonymous
I got it wrong i must have misplaced something...
anonymous
  • anonymous
i bet you forgot to distribute the - sign
anonymous
  • anonymous
\[\left(\begin{matrix}6x2y - (3x+2y) \\ x^2+5xy-6y^2 - (x^2+4xy-5y^2)\end{matrix}\right)\]
anonymous
  • anonymous
i think that is what i forgot...

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