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alexsu22

  • 4 years ago

Subract.

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  1. Walleye
    • 4 years ago
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    -

  2. alexsu22
    • 4 years ago
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    \[\left(\begin{matrix}6x_2y \\ x^2+5xy-6y^2\end{matrix}\right)-\left(\begin{matrix}3x+2y \\ x^2+4xy-5y^2\end{matrix}\right)\]

  3. Walleye
    • 4 years ago
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    do you know how to add and subtract vectors? \[\left(\begin{matrix}a \\ b\end{matrix}\right) + \left(\begin{matrix}c \\ d\end{matrix}\right) = \left(\begin{matrix}a+c \\ b+d\end{matrix}\right)\]

  4. alexsu22
    • 4 years ago
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    No i do not?

  5. across
    • 4 years ago
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    He literally told you how to up there.

  6. Walleye
    • 4 years ago
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    your a = 6x2y your c = 3x + 2y ... does this help at all?

  7. alexsu22
    • 4 years ago
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    Yes now i get it... and my bad across :/

  8. alexsu22
    • 4 years ago
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    I got it wrong i must have misplaced something...

  9. Walleye
    • 4 years ago
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    i bet you forgot to distribute the - sign

  10. Walleye
    • 4 years ago
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    \[\left(\begin{matrix}6x2y - (3x+2y) \\ x^2+5xy-6y^2 - (x^2+4xy-5y^2)\end{matrix}\right)\]

  11. alexsu22
    • 4 years ago
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    i think that is what i forgot...

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