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Sinz

  • 4 years ago

Multiply the expressions, and simplify. (8x3y-3) · (3x3y-3)

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  1. lilg132
    • 4 years ago
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    actually i'll let thomas do this one =)

  2. Sinz
    • 4 years ago
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    okay

  3. Walleye
    • 4 years ago
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    do you know how to distribute?

  4. Sinz
    • 4 years ago
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    some what yeah

  5. Walleye
    • 4 years ago
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    this is just a distribution problem but it will take a little longer to compute

  6. Sinz
    • 4 years ago
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    okay help me to start it and I should be able to figure it out I know 8*3 =24

  7. Sinz
    • 4 years ago
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    do you add like exponents

  8. Walleye
    • 4 years ago
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    sure your first term will be (8x3y * 3x3y)

  9. Walleye
    • 4 years ago
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    let me expand it out for you and then you can try to see the patteren

  10. Sinz
    • 4 years ago
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    okay

  11. Walleye
    • 4 years ago
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    \[(8x3y-3) * (3x3y-3) = (8x3y*3x3y) + (8x3y*-3) + (-3*3x3y) +(-3*-3)\]

  12. Walleye
    • 4 years ago
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    did my eqaution go off the screen for you?

  13. Sinz
    • 4 years ago
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    yeah

  14. Walleye
    • 4 years ago
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    haha sorry the part that is cut off is +(-3 * -3)

  15. Walleye
    • 4 years ago
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    all I did was FOIL it out. Now you have to go about simplying it.

  16. Sinz
    • 4 years ago
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    yeah but what about the exponents the problem was (8x^3y^-3) · (3x^3y^-3) sorry didn't see that when I posted it

  17. Sinz
    • 4 years ago
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    don't you add the exponents when multiplying the main part of the problem

  18. Walleye
    • 4 years ago
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    ah no problem you can slip them into the problem when you mutiply two exponents with the same base you can add the exponents for example \[x^3 * x^5 = x^8\]

  19. Sinz
    • 4 years ago
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    okay so then it is 24x^6y^-6 correct

  20. Walleye
    • 4 years ago
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    yes!!!!

  21. Walleye
    • 4 years ago
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    well done! that one can get messy

  22. Sinz
    • 4 years ago
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    okay thought it was right but wasn't sure thanks again

  23. Sinz
    • 4 years ago
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    yeah especially when it is posted wrong

  24. Sinz
    • 4 years ago
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    I think I have found a new website for tutoring

  25. Sinz
    • 4 years ago
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    everyone is so helpful

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