Here's the question you clicked on:
ali.athar
evaluaten limits
\[\lim_{x \rightarrow 1} x ^{3}-1/x ^{2}-1\]
\[\lim_{x \rightarrow 1} \frac{3x^2}{2x} = \frac{3}{2}\]
limx→1(x3−1/x2−1) limx→1((x-1)(x^2+x+1))/(x-1)(x+1) limx→1(x^2+x+1)/(x+1) 3/2 is the answer after applying limits check the formula for x3−1i have doubt in it