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mominanisar

  • 3 years ago

what is the laplace inverse of (s^4+6s-18)/(s^5-3s^4)?

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  1. sumbul
    • 3 years ago
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    use partial fractions and take s^4 common from denomiator it will be easy to solve

  2. sumbul
    • 3 years ago
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    and then use the formulae that laplace inverse of 1/s = 1 and laplace inverse of 1/s^2= t etc and laplace inverse of 1/s-3= \[e^{3t}\]

  3. mominanisar
    • 3 years ago
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    the answer is (e^(3t) )+t^3

  4. mominanisar
    • 3 years ago
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    would you please give me the solved question

  5. sumbul
    • 3 years ago
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    do you know how to make partial fractions??

  6. mominanisar
    • 3 years ago
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    yes

  7. sumbul
    • 3 years ago
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    then use partial fractions and it will be easy use the formulae i mentiond above

  8. sumbul
    • 3 years ago
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    is it form bsc?? methods

  9. mominanisar
    • 3 years ago
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    s^4+6s-18=A/s+B/s^2+C/s^3+D/s^4+E/s-3

  10. sumbul
    • 3 years ago
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    yes right and then find A,B,C,D,E AND IT WILL BE 101 PERCENT SIMPLE

  11. mominanisar
    • 3 years ago
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    ok thanks alot

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