x2 - 3x = 4 (the 2 is smal)

- anonymous

x2 - 3x = 4 (the 2 is smal)

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- lilg132

x^2 - 3x - 4 = 0
what two numbers added together give you -3 and multiply to give you -4?

- anonymous

A?

- lilg132

LOL

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

A) 1 4
B) 1 -4
C) -1 4
D) -1 -4

- Mimi_x3

Just use wolfram alpha if you are lazy

- lilg132

i'm not giving you anymore answers if you dont want to learn

- anonymous

i wanna learn just not too good at this lol :)

- anonymous

\[(x-4)(x+1)=0\]

- lilg132

well stop guessing and try and understand

- lilg132

what two numbers can i add together to give me -3

- anonymous

1+2

- lilg132

no that will give you +3 not -3

- lilg132

-4 + ? BIG CLUE

- anonymous

1-2?

- lilg132

that will give you -1

- anonymous

1+2-6?

- lilg132

i said two numbers

- lilg132

not three

- anonymous

0-3?

- lilg132

try taking a look at where i said BIG CLUE !

- lilg132

good your getting there

- lilg132

that would give you -3 but we need to find two numbers that give you -3 and the same two numbers need to multiply to give you -4

- anonymous

plz i only have 10 minutes left

- lilg132

its touching if you want to learn you will make more time

- anonymous

plz i want to learn but just dont have time right now

- anonymous

ok so you have x2 - 3x = 4
the first thing you want to do is equal this to zero, we can do that by subtracting 4
x^2-3x-4=0
Now, like what that person said, what can you multiply to get -4, and add to get -3?
now let's guess and check. 1 * 4 = 4, but 1 + 4 = 5, ew that won't work
hmm. 1 * -4 = -4, and 1 - 4 = -3
that works!
now we use these two numbers, 1 and -4 and plug it back into the original equation (take the -3x away)
x^2+1x-4x-4
basically what we did is split the -3 apart, because you see, 1x-4x equals -3x so it's basically the same thing, but the point of doing this is that you can factor by grouping.
so lets group the first two terms, x^2 and 1x, what two numbers, or variables, go into both of these? well, x does.
x
Now what's x divided by x^2? that's just x
x ( x
now what's x divided by 1x? 1.
x ( x +1 )
you know this is correct when you use the distributive propetry and get what you use to have|dw:1323571839146:dw|
now, let's factor the other two terms, -4x and -4
these look like they both go into -4
-4
now, -4x divided by 4? just x.
-4 ( x
-4 divided by -4? 1.
-4 (x+1)
Now, lets bring it all together. the numbers in the parentheses should be the same (you got x+1 in both, so it's right.
(x+1) now let's bring over the numbers that aren't in parentheses x and -4 just put those in parentheses like (x-4)
the factored version is
(x+1)(x-4)
now, we have to equal both of these to zero and solve like a regular algebra problem to get your two solutions
x+1=0
subtract 1 from both sides
x=-1
do the same thing to the other one
x-4=0
add 4 to both sides
x=4
those are your two solutions x=-1 and x=4

- anonymous

if you don't understand something tell me

- anonymous

so what letter is answer?

- anonymous

c

- anonymous

i just typed it above

- anonymous

thanx hun that worked :) <3

- anonymous

That's a miracle <3

- anonymous

well didn't you read what i wrote?

- anonymous

Well, all she cares is the letter

- lilg132

no you just wasted your time neverforgetvivistee

- anonymous

well flutter

- anonymous

flutter come on

- anonymous

big kisses hun, thanx :)

- anonymous

i put real thought into that

- anonymous

flutter you hot cutie u stupid feather

- lilg132

i've been trying for a while as well now but she just doesnt want to learn she doesn't have 'time' to learn apperently

- anonymous

She doesn't even understand the very basic of algebra.

Looking for something else?

Not the answer you are looking for? Search for more explanations.