A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1bonus question from an old test so it's suppose to be tricky...

Euler271
 3 years ago
Best ResponseYou've already chosen the best response.0well, this question seems flawed to me. the curve x^n can not really be defined. although, all curves of the form x^n, n>0 look the same, and that is exponential. The only point these have in common is (1,1). Do you know what your teacher meant by: find?

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1the question before this one asks to find the unit tangent vector T, curvature k, and unit normal vector N and i know that T=r'/r', k=(dT/dt)/r', and N=T'/T'

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1the difference is this asks to find all that in a space curve and this bonus question asks to find in a plane curve

Euler271
 3 years ago
Best ResponseYou've already chosen the best response.0lol, never mind, i thought it was basic algebra, not advanced linear algebra :P. i can't help at all with that, my bad :)

Jemurray3
 3 years ago
Best ResponseYou've already chosen the best response.1It's neither, its calculus. A plane curve is nothing but a space curve with no zero component. You could parameterize it like \[\vec{r} = <x,x^n>\] or \[\vec{r} = <x,x^n,0> \] if it would make you more comfortable.

Jemurray3
 3 years ago
Best ResponseYou've already chosen the best response.1I'm sorry, with no zcomponent :)

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1ok so if i use that, i should be able to get it..feel free to solve so i can check later, thx!!

Jemurray3
 3 years ago
Best ResponseYou've already chosen the best response.1So the tangent vector \[T = \frac{\vec{r'}}{r'} = \frac{<1,nx^{n1}>}{\sqrt{1+(nx^{n1})^2}}\] the curvature can also be written \[\kappa = \frac{x' y'' + x'' y'}{(x'^2+y'^2)^\frac{3}{2}}\] where the above variables are defined as \[\vec{r} = <x(t),y(t)> \] for some parameter t. We're actually using x itself as the parameter, so x' = 1 and x'' = 0. This yields \[\kappa = \frac{n(n1)x^{n2}}{(1 + n^2x^{2n2})^\frac{3}{2} } \]

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1your way seems much faster, easier, and cleaner. mine is getting too messy and it's getting too late
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.