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eashmore
 3 years ago
Best ResponseYou've already chosen the best response.1The zeros are the values of x that make the function equal to zero (also called a root). Here because the polynomial has a degree of 3, we will have three zeros. First, lets set the function equal to zero. \[6x^3  35x^2 +26x  5 = 0\]Let's move the five over, factor out an x, and obtain the following\[x \left( 6x^2  35x + 26 \right) = 5\]We can see that one of the zeros must be equal to 5. Now let's solve the remaining seconddegree polynomial to obtain the other two zeros. We can use the quadratic equation\[x = {b \pm \sqrt{b^2  4ac} \over 2a }\]

kiara23
 3 years ago
Best ResponseYou've already chosen the best response.0is this the answer ? 5,1/3 , –1/2

eashmore
 3 years ago
Best ResponseYou've already chosen the best response.1Check the signs of your roots.

robtobey
 3 years ago
Best ResponseYou've already chosen the best response.0\[6 x^335 x^2+26 x5=(x5) (2 x1) (3 x1) \]
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