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askme12345
 3 years ago
Best ResponseYou've already chosen the best response.1substitute all your x's for negative x :)

sonicfan12
 3 years ago
Best ResponseYou've already chosen the best response.0Will you show me an example please?

LagrangeSon678
 3 years ago
Best ResponseYou've already chosen the best response.0first count the sign changes in the original polynomial, the compute f(x) and count the sign changes

askme12345
 3 years ago
Best ResponseYou've already chosen the best response.1Sure  Lets say your equation is 5x^3 + 4x^2  5x So you have negative, positive, negative = this means 3 positive zeros (when youre solving for zeros) decartes rule says when you put x into the equation you'll get your negative zeros .. here we go 5(x)^3 + 4(x)^2 5(x) (All even powers, will become negative, odds stay the same) 5x^3  4x2 + 5x .. so we have postive to negative to positive .. therefore 3 positive zeros

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0purplemath has a good example and explanation

sonicfan12
 3 years ago
Best ResponseYou've already chosen the best response.0Thanx for the help! XD
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