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anilorap Group Title

in how many ways can 6 books be arrange on two shelves, such that there is at least 2 books on each shelve.

  • 2 years ago
  • 2 years ago

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  1. jacobmeir Group Title
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    from 6 choose 2 plus from 6 choose 3 plus from 6 choose 4 = 6*5/2 +6*4*3/(3*2) +6*4*3*2/(4*3*2)

    • 2 years ago
  2. Zarkon Group Title
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    are the books distinct or are they all the same.

    • 2 years ago
  3. anilorap Group Title
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    dont say.. they just books i guess in general

    • 2 years ago
  4. Zarkon Group Title
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    then there are 3 main ways to put the books on the shelf xx|xxxx xxx|xxx xxxx|xx each of which can be arranged 6! ways giving us a total of 6!*3=2160

    • 2 years ago
  5. anilorap Group Title
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    mmmm

    • 2 years ago
  6. jacobmeir Group Title
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    wow he got way more arrangements then i did

    • 2 years ago
  7. anilorap Group Title
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    well i was doing the combination.. like 6 choose 2 + 6 choose 3 +6 choose 4.. for the first shelf

    • 2 years ago
  8. anilorap Group Title
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    |dw:1323670745186:dw|

    • 2 years ago
  9. Zarkon Group Title
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    that is just for the 1st shelf?

    • 2 years ago
  10. anilorap Group Title
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    yes

    • 2 years ago
  11. anilorap Group Title
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    but if i multiply by two... i dont get ur answer tho

    • 2 years ago
  12. Zarkon Group Title
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    you par picking the number of books to be on the first shelf....you still need to arrange the books once you pick the number you want

    • 2 years ago
  13. Zarkon Group Title
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    *you ARE picking...

    • 2 years ago
  14. Zarkon Group Title
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    you could do this...\[{6\choose 2}2!4!+{6\choose 3}3!3!+{6\choose 4}4!2!=2160\]

    • 2 years ago
  15. anilorap Group Title
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    ohhh... u r multiplyinggg

    • 2 years ago
  16. anilorap Group Title
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    mmm.. wait so i do this

    • 2 years ago
  17. anilorap Group Title
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    |dw:1323671159497:dw|

    • 2 years ago
  18. anilorap Group Title
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    |dw:1323671255876:dw|

    • 2 years ago
  19. Zarkon Group Title
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    \[{6\choose4}=15\]

    • 2 years ago
  20. jacobmeir Group Title
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    from the way you wrote the problem, I doubt the arrangment on the shelf matters. I'd say the answer is 15 +20 +15 =50

    • 2 years ago
  21. anilorap Group Title
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    the problem says: Ali has six books and she wants to put them on two shelves, such that there is at least two books on each shelf. in how many ways can she do this?

    • 2 years ago
  22. Zarkon Group Title
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    it should matter...when you are choosing you are selecting 2 or 3 or 4 specific books to be on the first shelf....if you are doing this where order does not matter then there are only 3 ways to do it.

    • 2 years ago
  23. jacobmeir Group Title
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    abcd on top. abc ontop bc on top ac on top. that's more than 3 right there

    • 2 years ago
  24. Zarkon Group Title
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    2 books on the first 4 on the sec 3 books on the first 3 on the sec 4 books on the first 2 on the sec 3 wyas

    • 2 years ago
  25. Zarkon Group Title
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    *ways

    • 2 years ago
  26. anilorap Group Title
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    ok,, i got that..im clear up to that point

    • 2 years ago
  27. Zarkon Group Title
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    otherwise you have an order and the answer is 2160

    • 2 years ago
  28. anilorap Group Title
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    then

    • 2 years ago
  29. anilorap Group Title
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    Zarkon i got the first part... but i dont get the second :(

    • 2 years ago
  30. Zarkon Group Title
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    what part is that?

    • 2 years ago
  31. anilorap Group Title
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    |dw:1323671862157:dw| this part is correct u said... now i need to arrange them and u told me |dw:1323671932238:dw| to do this..

    • 2 years ago
  32. Zarkon Group Title
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    it is not 30 it is 15 15*2!4!=15*2*1*4*3*2*1=720 ...

    • 2 years ago
  33. Zarkon Group Title
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    720+720+720=2160

    • 2 years ago
  34. anilorap Group Title
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    ohhh,, i see what i did wrong... :(... let me do it again

    • 2 years ago
  35. anilorap Group Title
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    wowwww,, thanksssss u guys

    • 2 years ago
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