anonymous
  • anonymous
in how many ways can 6 books be arrange on two shelves, such that there is at least 2 books on each shelve.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
from 6 choose 2 plus from 6 choose 3 plus from 6 choose 4 = 6*5/2 +6*4*3/(3*2) +6*4*3*2/(4*3*2)
Zarkon
  • Zarkon
are the books distinct or are they all the same.
anonymous
  • anonymous
dont say.. they just books i guess in general

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More answers

Zarkon
  • Zarkon
then there are 3 main ways to put the books on the shelf xx|xxxx xxx|xxx xxxx|xx each of which can be arranged 6! ways giving us a total of 6!*3=2160
anonymous
  • anonymous
mmmm
anonymous
  • anonymous
wow he got way more arrangements then i did
anonymous
  • anonymous
well i was doing the combination.. like 6 choose 2 + 6 choose 3 +6 choose 4.. for the first shelf
anonymous
  • anonymous
|dw:1323670745186:dw|
Zarkon
  • Zarkon
that is just for the 1st shelf?
anonymous
  • anonymous
yes
anonymous
  • anonymous
but if i multiply by two... i dont get ur answer tho
Zarkon
  • Zarkon
you par picking the number of books to be on the first shelf....you still need to arrange the books once you pick the number you want
Zarkon
  • Zarkon
*you ARE picking...
Zarkon
  • Zarkon
you could do this...\[{6\choose 2}2!4!+{6\choose 3}3!3!+{6\choose 4}4!2!=2160\]
anonymous
  • anonymous
ohhh... u r multiplyinggg
anonymous
  • anonymous
mmm.. wait so i do this
anonymous
  • anonymous
|dw:1323671159497:dw|
anonymous
  • anonymous
|dw:1323671255876:dw|
Zarkon
  • Zarkon
\[{6\choose4}=15\]
anonymous
  • anonymous
from the way you wrote the problem, I doubt the arrangment on the shelf matters. I'd say the answer is 15 +20 +15 =50
anonymous
  • anonymous
the problem says: Ali has six books and she wants to put them on two shelves, such that there is at least two books on each shelf. in how many ways can she do this?
Zarkon
  • Zarkon
it should matter...when you are choosing you are selecting 2 or 3 or 4 specific books to be on the first shelf....if you are doing this where order does not matter then there are only 3 ways to do it.
anonymous
  • anonymous
abcd on top. abc ontop bc on top ac on top. that's more than 3 right there
Zarkon
  • Zarkon
2 books on the first 4 on the sec 3 books on the first 3 on the sec 4 books on the first 2 on the sec 3 wyas
Zarkon
  • Zarkon
*ways
anonymous
  • anonymous
ok,, i got that..im clear up to that point
Zarkon
  • Zarkon
otherwise you have an order and the answer is 2160
anonymous
  • anonymous
then
anonymous
  • anonymous
Zarkon i got the first part... but i dont get the second :(
Zarkon
  • Zarkon
what part is that?
anonymous
  • anonymous
|dw:1323671862157:dw| this part is correct u said... now i need to arrange them and u told me |dw:1323671932238:dw| to do this..
Zarkon
  • Zarkon
it is not 30 it is 15 15*2!4!=15*2*1*4*3*2*1=720 ...
Zarkon
  • Zarkon
720+720+720=2160
anonymous
  • anonymous
ohhh,, i see what i did wrong... :(... let me do it again
anonymous
  • anonymous
wowwww,, thanksssss u guys

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