## King 3 years ago If motion of a particle given below is x=u(t-2s)+a(t-2s)^2 A)initial velocity is u B)acceleration is a C)acceleration is 2a D)at t=2s particle is at origin More than 1 option can be right Please explain ure answer.

1. King

s is seconds just a unit

2. Ishaan94

A,C and D are true :-) Compare it with $$x = u\times t + \frac{1}{2}\times a \times t^2$$

3. King

actually ure wrong..i wont tell u the rite answer try it!!

4. Ishaan94

I can't be wrong

5. King

6. King

no u hav to expand then compare

7. Ishaan94

Na I don't have to expand since (t - 2) is time only (2 is in seconds and so is t)

8. King

but its not a(t-2s)^2 its supposed a/2

9. King

it at^2 ok but shouldnt it be (at^2)/2

10. Ishaan94

$\frac{1}{2}\times 2a\times (t - 2)^2$

11. King

initial velocity is not u C),D) is rite

12. Ishaan94

Initial velocity must be U!

13. King

its not..my sir explained but i frgt

14. King

pls expand once aand see what u get

15. Ishaan94

Okay I get what you meant

16. King

ahh now xplain

17. Ishaan94

Hmm because it's (t-2)^2 not t^2 so an extra co-efficient of t is there

18. King

oh yeah and btw my sir took x as xfinal - xinitial

19. Ishaan94

Okay!

20. King

hey explain!