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King
Group Title
If motion of a particle given below is
x=u(t2s)+a(t2s)^2
A)initial velocity is u
B)acceleration is a
C)acceleration is 2a
D)at t=2s particle is at origin
More than 1 option can be right
Please explain ure answer.
 2 years ago
 2 years ago
King Group Title
If motion of a particle given below is x=u(t2s)+a(t2s)^2 A)initial velocity is u B)acceleration is a C)acceleration is 2a D)at t=2s particle is at origin More than 1 option can be right Please explain ure answer.
 2 years ago
 2 years ago

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King Group TitleBest ResponseYou've already chosen the best response.0
s is seconds just a unit
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
A,C and D are true :) Compare it with \(x = u\times t + \frac{1}{2}\times a \times t^2\)
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
actually ure wrong..i wont tell u the rite answer try it!!
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
I can't be wrong
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
and please explain...
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
no u hav to expand then compare
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Na I don't have to expand since (t  2) is time only (2 is in seconds and so is t)
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
but its not a(t2s)^2 its supposed a/2
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
it at^2 ok but shouldnt it be (at^2)/2
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{1}{2}\times 2a\times (t  2)^2\]
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
initial velocity is not u C),D) is rite
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Initial velocity must be U!
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
its not..my sir explained but i frgt
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
pls expand once aand see what u get
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Okay I get what you meant
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
ahh now xplain
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Hmm because it's (t2)^2 not t^2 so an extra coefficient of t is there
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
oh yeah and btw my sir took x as xfinal  xinitial
 2 years ago
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