King
If motion of a particle given below is
x=u(t-2s)+a(t-2s)^2
A)initial velocity is u
B)acceleration is a
C)acceleration is 2a
D)at t=2s particle is at origin
More than 1 option can be right
Please explain ure answer.
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King
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s is seconds just a unit
Ishaan94
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A,C and D are true :-)
Compare it with \(x = u\times t + \frac{1}{2}\times a \times t^2\)
King
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actually ure wrong..i wont tell u the rite answer try it!!
Ishaan94
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I can't be wrong
King
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and please explain...
King
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no u hav to expand then compare
Ishaan94
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Na I don't have to expand since (t - 2) is time only (2 is in seconds and so is t)
King
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but its not a(t-2s)^2 its supposed a/2
King
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it at^2 ok but shouldnt it be (at^2)/2
Ishaan94
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\[\frac{1}{2}\times 2a\times (t - 2)^2\]
King
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initial velocity is not u C),D) is rite
Ishaan94
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Initial velocity must be U!
King
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its not..my sir explained but i frgt
King
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pls expand once aand see what u get
Ishaan94
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Okay I get what you meant
King
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ahh now xplain
Ishaan94
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Hmm because it's (t-2)^2 not t^2 so an extra co-efficient of t is there
King
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oh yeah and btw my sir took x as xfinal - xinitial
Ishaan94
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Okay!
King
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hey explain!