## xEnOnn Group Title Suppose there are 5 students in a class. What is the probability of having exactly 3 students who have the same birthday? I am thinking I should have $365 \times 365 \times 364 \times 363 \times 362$ and then divide all of it by 5. But it doesn't feel right. What should I do to find out the probability? 2 years ago 2 years ago

1. ash2326 Group Title

three students have b'day o same day, rest two will have on different days so no. of cases =365*364*363 total no. of cases =365*365*365*365*365 so probability=364*363/(365)^4

2. ash2326 Group Title

no of required cases =365*1*1*364*363

3. xEnOnn Group Title

Why is it (365)^4 and not (365)^5?

4. ash2326 Group Title

one 365 got cancelled by the numerator's 365

5. xEnOnn Group Title

oh i see.... Thank you so much! :)

6. ash2326 Group Title

welcome xEnOnn