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xEnOnn Group Title

Suppose there are 5 students in a class. What is the probability of having exactly 3 students who have the same birthday? I am thinking I should have \[365 \times 365 \times 364 \times 363 \times 362\] and then divide all of it by 5. But it doesn't feel right. What should I do to find out the probability?

  • 2 years ago
  • 2 years ago

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  1. ash2326 Group Title
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    three students have b'day o same day, rest two will have on different days so no. of cases =365*364*363 total no. of cases =365*365*365*365*365 so probability=364*363/(365)^4

    • 2 years ago
  2. ash2326 Group Title
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    no of required cases =365*1*1*364*363

    • 2 years ago
  3. xEnOnn Group Title
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    Why is it (365)^4 and not (365)^5?

    • 2 years ago
  4. ash2326 Group Title
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    one 365 got cancelled by the numerator's 365

    • 2 years ago
  5. xEnOnn Group Title
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    oh i see.... Thank you so much! :)

    • 2 years ago
  6. ash2326 Group Title
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    welcome xEnOnn

    • 2 years ago
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