anonymous
  • anonymous
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ? sin^2 θ cos^2 θ 2sinθ (cscθ) 2cos^2 θ
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
2cos^2 θ
anonymous
  • anonymous
Are you sure?
anonymous
  • anonymous
cot is cos/sin

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anonymous
  • anonymous
so it can be written as 2sincos^2 / sin
ash2326
  • ash2326
2 sin theta cos theta*cot theta co=cos/sin 2 sin theta*cos theta*cos theta /sin theta we get 2 cos^2 theta
anonymous
  • anonymous
which then simplifies to 2cos^2
anonymous
  • anonymous
O thanks !

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