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Sbdenney

  • 4 years ago

PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ? sin^2 θ cos^2 θ 2sinθ (cscθ) 2cos^2 θ

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  1. ghass1978
    • 4 years ago
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    2cos^2 θ

  2. Sbdenney
    • 4 years ago
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    Are you sure?

  3. mwmnj
    • 4 years ago
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    cot is cos/sin

  4. mwmnj
    • 4 years ago
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    so it can be written as 2sincos^2 / sin

  5. ash2326
    • 4 years ago
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    2 sin theta cos theta*cot theta co=cos/sin 2 sin theta*cos theta*cos theta /sin theta we get 2 cos^2 theta

  6. mwmnj
    • 4 years ago
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    which then simplifies to 2cos^2

  7. Sbdenney
    • 4 years ago
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    O thanks !

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