Sbdenney
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ?
sin^2 θ
cos^2 θ
2sinθ (cscθ)
2cos^2 θ



This Question is Closed

ghass1978
Best Response
You've already chosen the best response.
1
2cos^2 θ

Sbdenney
Best Response
You've already chosen the best response.
0
Are you sure?

mwmnj
Best Response
You've already chosen the best response.
0
cot is cos/sin

mwmnj
Best Response
You've already chosen the best response.
0
so it can be written as 2sincos^2 / sin

ash2326
Best Response
You've already chosen the best response.
0
2 sin theta cos theta*cot theta
co=cos/sin
2 sin theta*cos theta*cos theta /sin theta
we get 2 cos^2 theta

mwmnj
Best Response
You've already chosen the best response.
0
which then simplifies to 2cos^2

Sbdenney
Best Response
You've already chosen the best response.
0
O thanks
!