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Sbdenney
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PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ?
sin^2 θ
cos^2 θ
2sinθ (cscθ)
2cos^2 θ
 2 years ago
 2 years ago
Sbdenney Group Title
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ? sin^2 θ cos^2 θ 2sinθ (cscθ) 2cos^2 θ
 2 years ago
 2 years ago

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Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
Are you sure?
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
cot is cos/sin
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
so it can be written as 2sincos^2 / sin
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
2 sin theta cos theta*cot theta co=cos/sin 2 sin theta*cos theta*cos theta /sin theta we get 2 cos^2 theta
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
which then simplifies to 2cos^2
 2 years ago

Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
O thanks !
 2 years ago
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