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anonymous
 4 years ago
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ?
sin^2 θ
cos^2 θ
2sinθ (cscθ)
2cos^2 θ
anonymous
 4 years ago
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ? sin^2 θ cos^2 θ 2sinθ (cscθ) 2cos^2 θ

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it can be written as 2sincos^2 / sin

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.02 sin theta cos theta*cot theta co=cos/sin 2 sin theta*cos theta*cos theta /sin theta we get 2 cos^2 theta

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which then simplifies to 2cos^2
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