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mwmnj
 3 years ago
Best ResponseYou've already chosen the best response.0hmm, dunno beside just distributing

Tyler1992
 3 years ago
Best ResponseYou've already chosen the best response.2i get just \[\sin^2\theta + cox^2 \theta\]

Sbdenney
 3 years ago
Best ResponseYou've already chosen the best response.0whats the 2nd part of it

Tyler1992
 3 years ago
Best ResponseYou've already chosen the best response.2I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]

Sbdenney
 3 years ago
Best ResponseYou've already chosen the best response.0sin^2 θ (csc^2 θ) ? is that what you meant?

mwmnj
 3 years ago
Best ResponseYou've already chosen the best response.0then you have 1+cos^2=1/sin^2

mwmnj
 3 years ago
Best ResponseYou've already chosen the best response.0so then you multiply sin^2 back to have sin^4 = 1

Sbdenney
 3 years ago
Best ResponseYou've already chosen the best response.0ALl my answers start with sin2 θ

Tyler1992
 3 years ago
Best ResponseYou've already chosen the best response.2Then you get sin^2 + cos^2 which is 1

DHASHNI
 3 years ago
Best ResponseYou've already chosen the best response.1sin^2 θ (1 + cot^2 θ) = 1 sin^2 θ + cos^2 θ = 1

Tyler1992
 3 years ago
Best ResponseYou've already chosen the best response.2\[Answer = \sin^2\theta + \cos^2 \theta\]
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