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hmm, dunno beside just distributing

dint see a trig sub

:/

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trig sub?

i get just \[\sin^2\theta + cox^2 \theta\]

How?

Whats that Tyler?

whats the 2nd part of it

Oh wait actually

divide sin^2

I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]

sin^2 θ (csc^2 θ) ?
is that what you meant?

then you have 1+cos^2=1/sin^2

which is -sin^2=1/sin^2

so then you multiply sin^2 back to have -sin^4 = 1

ALl my answers start with sin2 θ

Then you get sin^2 + cos^2 which is 1

sin^2 θ (1 + cot^2 θ) = 1
sin^2 θ + cos^2 θ = 1

:(

??

\[Answer = \sin^2\theta + \cos^2 \theta\]

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