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Sbdenney

  • 3 years ago

HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is

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  1. mwmnj
    • 3 years ago
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    hmm, dunno beside just distributing

  2. mwmnj
    • 3 years ago
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    dint see a trig sub

  3. Sbdenney
    • 3 years ago
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    :/

  4. Sbdenney
    • 3 years ago
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    trig sub?

  5. Tyler1992
    • 3 years ago
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    i get just \[\sin^2\theta + cox^2 \theta\]

  6. mwmnj
    • 3 years ago
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    How?

  7. Sbdenney
    • 3 years ago
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    Whats that Tyler?

  8. Sbdenney
    • 3 years ago
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    whats the 2nd part of it

  9. mwmnj
    • 3 years ago
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    Oh wait actually

  10. mwmnj
    • 3 years ago
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    divide sin^2

  11. Tyler1992
    • 3 years ago
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    I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]

  12. Sbdenney
    • 3 years ago
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    sin^2 θ (csc^2 θ) ? is that what you meant?

  13. mwmnj
    • 3 years ago
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    then you have 1+cos^2=1/sin^2

  14. mwmnj
    • 3 years ago
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    which is -sin^2=1/sin^2

  15. mwmnj
    • 3 years ago
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    so then you multiply sin^2 back to have -sin^4 = 1

  16. Sbdenney
    • 3 years ago
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    ALl my answers start with sin2 θ

  17. Tyler1992
    • 3 years ago
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    Then you get sin^2 + cos^2 which is 1

  18. DHASHNI
    • 3 years ago
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    sin^2 θ (1 + cot^2 θ) = 1 sin^2 θ + cos^2 θ = 1

  19. Sbdenney
    • 3 years ago
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    :(

  20. Tyler1992
    • 3 years ago
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    ??

  21. Tyler1992
    • 3 years ago
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    \[Answer = \sin^2\theta + \cos^2 \theta\]

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