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Sbdenney

HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is

  • 2 years ago
  • 2 years ago

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  1. mwmnj
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    hmm, dunno beside just distributing

    • 2 years ago
  2. mwmnj
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    dint see a trig sub

    • 2 years ago
  3. Sbdenney
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    :/

    • 2 years ago
  4. Sbdenney
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    trig sub?

    • 2 years ago
  5. Tyler1992
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    i get just \[\sin^2\theta + cox^2 \theta\]

    • 2 years ago
  6. mwmnj
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    How?

    • 2 years ago
  7. Sbdenney
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    Whats that Tyler?

    • 2 years ago
  8. Sbdenney
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    whats the 2nd part of it

    • 2 years ago
  9. mwmnj
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    Oh wait actually

    • 2 years ago
  10. mwmnj
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    divide sin^2

    • 2 years ago
  11. Tyler1992
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    I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]

    • 2 years ago
  12. Sbdenney
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    sin^2 θ (csc^2 θ) ? is that what you meant?

    • 2 years ago
  13. mwmnj
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    then you have 1+cos^2=1/sin^2

    • 2 years ago
  14. mwmnj
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    which is -sin^2=1/sin^2

    • 2 years ago
  15. mwmnj
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    so then you multiply sin^2 back to have -sin^4 = 1

    • 2 years ago
  16. Sbdenney
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    ALl my answers start with sin2 θ

    • 2 years ago
  17. Tyler1992
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    Then you get sin^2 + cos^2 which is 1

    • 2 years ago
  18. DHASHNI
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    sin^2 θ (1 + cot^2 θ) = 1 sin^2 θ + cos^2 θ = 1

    • 2 years ago
  19. Sbdenney
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    :(

    • 2 years ago
  20. Tyler1992
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    ??

    • 2 years ago
  21. Tyler1992
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    \[Answer = \sin^2\theta + \cos^2 \theta\]

    • 2 years ago
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