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Sbdenney
Group Title
HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is
 2 years ago
 2 years ago
Sbdenney Group Title
HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is
 2 years ago
 2 years ago

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mwmnj Group TitleBest ResponseYou've already chosen the best response.0
hmm, dunno beside just distributing
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
dint see a trig sub
 2 years ago

Tyler1992 Group TitleBest ResponseYou've already chosen the best response.2
i get just \[\sin^2\theta + cox^2 \theta\]
 2 years ago

Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
Whats that Tyler?
 2 years ago

Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
whats the 2nd part of it
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
Oh wait actually
 2 years ago

Tyler1992 Group TitleBest ResponseYou've already chosen the best response.2
I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]
 2 years ago

Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
sin^2 θ (csc^2 θ) ? is that what you meant?
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
then you have 1+cos^2=1/sin^2
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
which is sin^2=1/sin^2
 2 years ago

mwmnj Group TitleBest ResponseYou've already chosen the best response.0
so then you multiply sin^2 back to have sin^4 = 1
 2 years ago

Sbdenney Group TitleBest ResponseYou've already chosen the best response.0
ALl my answers start with sin2 θ
 2 years ago

Tyler1992 Group TitleBest ResponseYou've already chosen the best response.2
Then you get sin^2 + cos^2 which is 1
 2 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.1
sin^2 θ (1 + cot^2 θ) = 1 sin^2 θ + cos^2 θ = 1
 2 years ago

Tyler1992 Group TitleBest ResponseYou've already chosen the best response.2
\[Answer = \sin^2\theta + \cos^2 \theta\]
 2 years ago
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