anonymous
  • anonymous
HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
hmm, dunno beside just distributing
anonymous
  • anonymous
dint see a trig sub
anonymous
  • anonymous
:/

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anonymous
  • anonymous
trig sub?
anonymous
  • anonymous
i get just \[\sin^2\theta + cox^2 \theta\]
anonymous
  • anonymous
How?
anonymous
  • anonymous
Whats that Tyler?
anonymous
  • anonymous
whats the 2nd part of it
anonymous
  • anonymous
Oh wait actually
anonymous
  • anonymous
divide sin^2
anonymous
  • anonymous
I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]
anonymous
  • anonymous
sin^2 θ (csc^2 θ) ? is that what you meant?
anonymous
  • anonymous
then you have 1+cos^2=1/sin^2
anonymous
  • anonymous
which is -sin^2=1/sin^2
anonymous
  • anonymous
so then you multiply sin^2 back to have -sin^4 = 1
anonymous
  • anonymous
ALl my answers start with sin2 θ
anonymous
  • anonymous
Then you get sin^2 + cos^2 which is 1
anonymous
  • anonymous
sin^2 θ (1 + cot^2 θ) = 1 sin^2 θ + cos^2 θ = 1
anonymous
  • anonymous
:(
anonymous
  • anonymous
??
anonymous
  • anonymous
\[Answer = \sin^2\theta + \cos^2 \theta\]

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