anonymous
  • anonymous
Simplify:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
simplify what?
lilg132
  • lilg132
simplified
anonymous
  • anonymous
\[2x-2y \over 3x+3y \] . \[6x+6y \over x ^{2}-y ^{2}\]

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More answers

anonymous
  • anonymous
Answer choices are: A. 4 B. \[2 \over 3(x-y)\] C. \[4 \over x+y\]
anonymous
  • anonymous
I put the . there to show its times because I don't know how to put the dot in between the problems
anonymous
  • anonymous
Yes that is the problem
anonymous
  • anonymous
\[\frac{2x-2y}{3x+3y}\times \frac{6x+6y}{x^2-y^2}\]
anonymous
  • anonymous
\[\frac{4}{x+y}\]
anonymous
  • anonymous
lot of factoring and canceling for this one you need the steps?
anonymous
  • anonymous
Yes please! (:
anonymous
  • anonymous
actually factors as this \[\frac{2(x-y)6(x+y)}{3(x+y)(x+y)(x-y)}\]
anonymous
  • anonymous
What do I have to do to factor it? I'm confused.
anonymous
  • anonymous
\[2x-2y=2(x-y)\]
anonymous
  • anonymous
\[6x+6y=6(x+y)\]
anonymous
  • anonymous
\[3x+3y=3(x+y)\]
anonymous
  • anonymous
\[x^2-y^2=(x+y)(x-y)\]
anonymous
  • anonymous
so you factor as much as you can to see what factors you might have in common in the numerator and denominator. then you cancel each factor you have in common to reduce the fraction
anonymous
  • anonymous
Alright thanks! (:
anonymous
  • anonymous
when you get this \[\frac{2(x-y)6(x+y)}{3(x+y)(x+y)(x-y)}\] then you get rid of all common factors
anonymous
  • anonymous
\[\frac{2\cancel{(x-y)}6(x+y)}{3(x+y)(x+y)\cancel{(x-y)}}\]
anonymous
  • anonymous
\[\frac{12(x+y)}{3(x+y)(x+y)}\]
anonymous
  • anonymous
\[\frac{12\cancel{(x+y)}}{3\cancel{(x+y)}(x+y)}\]
anonymous
  • anonymous
so finally you get \[\frac{4}{x+y}\]
anonymous
  • anonymous
Exactly what I was thinking!! (: Thank you very much!!
anonymous
  • anonymous
yw

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