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meow18
 3 years ago
Best ResponseYou've already chosen the best response.0\[2x2y \over 3x+3y \] . \[6x+6y \over x ^{2}y ^{2}\]

meow18
 3 years ago
Best ResponseYou've already chosen the best response.0Answer choices are: A. 4 B. \[2 \over 3(xy)\] C. \[4 \over x+y\]

meow18
 3 years ago
Best ResponseYou've already chosen the best response.0I put the . there to show its times because I don't know how to put the dot in between the problems

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{2x2y}{3x+3y}\times \frac{6x+6y}{x^2y^2}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2lot of factoring and canceling for this one you need the steps?

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2actually factors as this \[\frac{2(xy)6(x+y)}{3(x+y)(x+y)(xy)}\]

meow18
 3 years ago
Best ResponseYou've already chosen the best response.0What do I have to do to factor it? I'm confused.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[x^2y^2=(x+y)(xy)\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2so you factor as much as you can to see what factors you might have in common in the numerator and denominator. then you cancel each factor you have in common to reduce the fraction

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2when you get this \[\frac{2(xy)6(x+y)}{3(x+y)(x+y)(xy)}\] then you get rid of all common factors

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{2\cancel{(xy)}6(x+y)}{3(x+y)(x+y)\cancel{(xy)}}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{12(x+y)}{3(x+y)(x+y)}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{12\cancel{(x+y)}}{3\cancel{(x+y)}(x+y)}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.2so finally you get \[\frac{4}{x+y}\]

meow18
 3 years ago
Best ResponseYou've already chosen the best response.0Exactly what I was thinking!! (: Thank you very much!!
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