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Mertsj
 5 years ago
f'(x) = (x^21)/x, f(1) = .5 and f(1) = 0
Find f(x)
Mertsj
 5 years ago
f'(x) = (x^21)/x, f(1) = .5 and f(1) = 0 Find f(x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f'(x)=\frac{x^21}{x}=x\frac{1}{x}\] so \[f(x)=\frac{x^2}{2}\ln(x)+C\] and there is no way that i can see that \[f(1)\] exists. what am i missing?

Mertsj
 5 years ago
Best ResponseYou've already chosen the best response.2I thought the same thing but the textbook gives both of those values.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=x ^{3}/3+lnx+c\]

Mertsj
 5 years ago
Best ResponseYou've already chosen the best response.2Actually, isn't the integral of 1/x lnx?
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