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1/3 come from differentiating u so you have du=3dx. solve for dx=1/3du

right i got that but i don't get where the 2/3*u^(3/2) comes from

i don't see 2/3. what you posted is 1/3 and u^1/2

in the rest of the text (1/3)*[(2/3)u^(3/2)}

o you mean the final answer? say you have to integrate x^2 dx. your answer is (x^2+1)/(2+1) right?

yeah

thank you i don't know why i wasn't seeing that

np, 2/3 on the bottom was flipped so gets hard to spot