Bellabambina223
Find the exact value of sin(T pi/6) when sin(t)=1/3 and cos(t)=Rad8/3



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amistre64
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\[sin(a+b)=sin(a)cos(b)+sin(b)cos(a)\]

amistre64
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in this case: a = T and b = pi/6 but not sure if that fits too well

amistre64
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that might work, even with the funny looking decimal

JoãoVitorMC
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ops there is a error there i will correct that

myininaya
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what funny looking decimal?

myininaya
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T=t?

JoãoVitorMC
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\[\sin(T  \pi/6) = \sin(T)\cos(\pi/6)\sin(\pi/6)\cos(T)\]\[\sqrt{3}/6  0,0232 = 0,2654\]

Bellabambina223
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so basically use the double angle formula?

JoãoVitorMC
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yes

myininaya
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\[\frac{1}{3} \cdot \frac{\sqrt{3}}{2}\frac{1}{2} \cdot \frac{\sqrt{8}}{3}\]

Bellabambina223
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oh did you get that from a chart myininaya?

JoãoVitorMC
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Remember that \[\sin(a \pm b)= \sin(a)\cos(b) \pm \sin(b)\cos(a)\]

Bellabambina223
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ok.. yes

myininaya
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yep bella
\[\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}; \sin(\frac{\pi}{6})=\frac{1}{2}\]

Bellabambina223
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ok thank you!

amistre64
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across the pond they use the "," as a "."