## Bellabambina223 3 years ago Find the exact value of sin(T -pi/6) when sin(t)=1/3 and cos(t)=Rad8/3

1. amistre64

$sin(a+b)=sin(a)cos(b)+sin(b)cos(a)$

2. amistre64

in this case: a = T and b = -pi/6 but not sure if that fits too well

3. amistre64

that might work, even with the funny looking decimal

4. JoãoVitorMC

ops there is a error there i will correct that

5. myininaya

what funny looking decimal?

6. myininaya

T=t?

7. JoãoVitorMC

$\sin(T - \pi/6) = \sin(T)\cos(\pi/6)-\sin(\pi/6)\cos(T)$$\sqrt{3}/6 - 0,0232 = 0,2654$

8. Bellabambina223

so basically use the double angle formula?

9. JoãoVitorMC

yes

10. myininaya

$\frac{1}{3} \cdot \frac{\sqrt{3}}{2}-\frac{1}{2} \cdot \frac{\sqrt{8}}{3}$

11. Bellabambina223

oh did you get that from a chart myininaya?

12. JoãoVitorMC

Remember that $\sin(a \pm b)= \sin(a)\cos(b) \pm \sin(b)\cos(a)$

13. Bellabambina223

ok.. yes

14. myininaya

yep bella $\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}; \sin(\frac{\pi}{6})=\frac{1}{2}$

15. Bellabambina223

ok thank you!

16. amistre64

across the pond they use the "," as a "."