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Bellabambina223 Group Title

Find the exact value of sin(T -pi/6) when sin(t)=1/3 and cos(t)=Rad8/3

  • 3 years ago
  • 3 years ago

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  1. amistre64 Group Title
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    \[sin(a+b)=sin(a)cos(b)+sin(b)cos(a)\]

    • 3 years ago
  2. amistre64 Group Title
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    in this case: a = T and b = -pi/6 but not sure if that fits too well

    • 3 years ago
  3. amistre64 Group Title
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    that might work, even with the funny looking decimal

    • 3 years ago
  4. JoãoVitorMC Group Title
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    ops there is a error there i will correct that

    • 3 years ago
  5. myininaya Group Title
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    what funny looking decimal?

    • 3 years ago
  6. myininaya Group Title
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    T=t?

    • 3 years ago
  7. JoãoVitorMC Group Title
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    \[\sin(T - \pi/6) = \sin(T)\cos(\pi/6)-\sin(\pi/6)\cos(T)\]\[\sqrt{3}/6 - 0,0232 = 0,2654\]

    • 3 years ago
  8. Bellabambina223 Group Title
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    so basically use the double angle formula?

    • 3 years ago
  9. JoãoVitorMC Group Title
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    yes

    • 3 years ago
  10. myininaya Group Title
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    \[\frac{1}{3} \cdot \frac{\sqrt{3}}{2}-\frac{1}{2} \cdot \frac{\sqrt{8}}{3}\]

    • 3 years ago
  11. Bellabambina223 Group Title
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    oh did you get that from a chart myininaya?

    • 3 years ago
  12. JoãoVitorMC Group Title
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    Remember that \[\sin(a \pm b)= \sin(a)\cos(b) \pm \sin(b)\cos(a)\]

    • 3 years ago
  13. Bellabambina223 Group Title
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    ok.. yes

    • 3 years ago
  14. myininaya Group Title
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    yep bella \[\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}; \sin(\frac{\pi}{6})=\frac{1}{2}\]

    • 3 years ago
  15. Bellabambina223 Group Title
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    ok thank you!

    • 3 years ago
  16. amistre64 Group Title
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    across the pond they use the "," as a "."

    • 3 years ago
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