agdgdgdgwngo
Find all numbers x for which |x - 3| = 8
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myininaya
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really?
agdgdgdgwngo
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there are harder ones coming after this one
myininaya
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lol
agdgdgdgwngo
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I just want to do a sanity check before I tackle the other ones
myininaya
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you know what you should do?
agdgdgdgwngo
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abs(x-3) = x-3 if x-3 > 0 else -(x-3)
myininaya
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you should ask them to solve both of these
|x-3| <-8
and |x-3|=-8
JoãoVitorMC
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x-3 = 8
x= 11
and
-(x-3) = 8
-x+3 = 8
x = -5
myininaya
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i bet you a lot of them would get it wrong
agdgdgdgwngo
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lol that is the very next question
myininaya
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i don't know how many times i have told me on here |something| does not have negative output so |f(x)|=-8 has no solution
|f(x)|>0 is never less than 0
agdgdgdgwngo
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so x-3 = 8 or x-3 = -8
so -5 <= x <= 11 is that right?
agdgdgdgwngo
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lol I'm wrong
myininaya
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or you still talking about the equation you gave?
agdgdgdgwngo
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yes
myininaya
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that one guy has it right
agdgdgdgwngo
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yeah :-D
myininaya
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did you mean for it to be an inequality?
agdgdgdgwngo
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no he's right
myininaya
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ok
myininaya
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omg i'm so bored
myininaya
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i'm gonna go
Meron
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+-11
Meron
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oh sorry i mean x=+-5