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agdgdgdgwngoBest ResponseYou've already chosen the best response.0
there are harder ones coming after this one
 2 years ago

agdgdgdgwngoBest ResponseYou've already chosen the best response.0
I just want to do a sanity check before I tackle the other ones
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
you know what you should do?
 2 years ago

agdgdgdgwngoBest ResponseYou've already chosen the best response.0
abs(x3) = x3 if x3 > 0 else (x3)
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
you should ask them to solve both of these x3 <8 and x3=8
 2 years ago

JoãoVitorMCBest ResponseYou've already chosen the best response.2
x3 = 8 x= 11 and (x3) = 8 x+3 = 8 x = 5
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
i bet you a lot of them would get it wrong
 2 years ago

agdgdgdgwngoBest ResponseYou've already chosen the best response.0
lol that is the very next question
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
i don't know how many times i have told me on here something does not have negative output so f(x)=8 has no solution f(x)>0 is never less than 0
 2 years ago

agdgdgdgwngoBest ResponseYou've already chosen the best response.0
so x3 = 8 or x3 = 8 so 5 <= x <= 11 is that right?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
or you still talking about the equation you gave?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
that one guy has it right
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
did you mean for it to be an inequality?
 2 years ago
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