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Find all numbers x for which |x - 3| = 8

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there are harder ones coming after this one

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Other answers:

I just want to do a sanity check before I tackle the other ones
you know what you should do?
abs(x-3) = x-3 if x-3 > 0 else -(x-3)
you should ask them to solve both of these |x-3| <-8 and |x-3|=-8
x-3 = 8 x= 11 and -(x-3) = 8 -x+3 = 8 x = -5
i bet you a lot of them would get it wrong
lol that is the very next question
i don't know how many times i have told me on here |something| does not have negative output so |f(x)|=-8 has no solution |f(x)|>0 is never less than 0
so x-3 = 8 or x-3 = -8 so -5 <= x <= 11 is that right?
lol I'm wrong
or you still talking about the equation you gave?
that one guy has it right
yeah :-D
did you mean for it to be an inequality?
no he's right
omg i'm so bored
i'm gonna go
oh sorry i mean x=+-5

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