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agdgdgdgwngo

Find all numbers x for which |x - 3| = 8

  • 2 years ago
  • 2 years ago

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  1. myininaya
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    really?

    • 2 years ago
  2. agdgdgdgwngo
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    there are harder ones coming after this one

    • 2 years ago
  3. myininaya
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    lol

    • 2 years ago
  4. agdgdgdgwngo
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    I just want to do a sanity check before I tackle the other ones

    • 2 years ago
  5. myininaya
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    you know what you should do?

    • 2 years ago
  6. agdgdgdgwngo
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    abs(x-3) = x-3 if x-3 > 0 else -(x-3)

    • 2 years ago
  7. myininaya
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    you should ask them to solve both of these |x-3| <-8 and |x-3|=-8

    • 2 years ago
  8. JoãoVitorMC
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    x-3 = 8 x= 11 and -(x-3) = 8 -x+3 = 8 x = -5

    • 2 years ago
  9. myininaya
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    i bet you a lot of them would get it wrong

    • 2 years ago
  10. agdgdgdgwngo
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    lol that is the very next question

    • 2 years ago
  11. myininaya
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    i don't know how many times i have told me on here |something| does not have negative output so |f(x)|=-8 has no solution |f(x)|>0 is never less than 0

    • 2 years ago
  12. agdgdgdgwngo
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    so x-3 = 8 or x-3 = -8 so -5 <= x <= 11 is that right?

    • 2 years ago
  13. agdgdgdgwngo
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    lol I'm wrong

    • 2 years ago
  14. myininaya
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    or you still talking about the equation you gave?

    • 2 years ago
  15. agdgdgdgwngo
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    yes

    • 2 years ago
  16. myininaya
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    that one guy has it right

    • 2 years ago
  17. agdgdgdgwngo
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    yeah :-D

    • 2 years ago
  18. myininaya
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    did you mean for it to be an inequality?

    • 2 years ago
  19. agdgdgdgwngo
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    no he's right

    • 2 years ago
  20. myininaya
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    ok

    • 2 years ago
  21. myininaya
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    omg i'm so bored

    • 2 years ago
  22. myininaya
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    i'm gonna go

    • 2 years ago
  23. Meron
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    +-11

    • 2 years ago
  24. Meron
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    oh sorry i mean x=+-5

    • 2 years ago
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