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agdgdgdgwngo

  • 4 years ago

Find all numbers x for which |x - 3| = 8

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  1. myininaya
    • 4 years ago
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    really?

  2. agdgdgdgwngo
    • 4 years ago
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    there are harder ones coming after this one

  3. myininaya
    • 4 years ago
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    lol

  4. agdgdgdgwngo
    • 4 years ago
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    I just want to do a sanity check before I tackle the other ones

  5. myininaya
    • 4 years ago
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    you know what you should do?

  6. agdgdgdgwngo
    • 4 years ago
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    abs(x-3) = x-3 if x-3 > 0 else -(x-3)

  7. myininaya
    • 4 years ago
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    you should ask them to solve both of these |x-3| <-8 and |x-3|=-8

  8. JoãoVitorMC
    • 4 years ago
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    x-3 = 8 x= 11 and -(x-3) = 8 -x+3 = 8 x = -5

  9. myininaya
    • 4 years ago
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    i bet you a lot of them would get it wrong

  10. agdgdgdgwngo
    • 4 years ago
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    lol that is the very next question

  11. myininaya
    • 4 years ago
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    i don't know how many times i have told me on here |something| does not have negative output so |f(x)|=-8 has no solution |f(x)|>0 is never less than 0

  12. agdgdgdgwngo
    • 4 years ago
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    so x-3 = 8 or x-3 = -8 so -5 <= x <= 11 is that right?

  13. agdgdgdgwngo
    • 4 years ago
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    lol I'm wrong

  14. myininaya
    • 4 years ago
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    or you still talking about the equation you gave?

  15. agdgdgdgwngo
    • 4 years ago
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    yes

  16. myininaya
    • 4 years ago
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    that one guy has it right

  17. agdgdgdgwngo
    • 4 years ago
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    yeah :-D

  18. myininaya
    • 4 years ago
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    did you mean for it to be an inequality?

  19. agdgdgdgwngo
    • 4 years ago
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    no he's right

  20. myininaya
    • 4 years ago
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    ok

  21. myininaya
    • 4 years ago
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    omg i'm so bored

  22. myininaya
    • 4 years ago
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    i'm gonna go

  23. Meron
    • 4 years ago
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    +-11

  24. Meron
    • 4 years ago
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    oh sorry i mean x=+-5

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