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FreeTrader

  • 4 years ago

Can you please help me with a little algebra? I just need to sprinkle some solving powder on it to get started...

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  1. FreeTrader
    • 4 years ago
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    \[y = (x-1)/(2x+3)\]

  2. FreeTrader
    • 4 years ago
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    I am attempting to solve for x.

  3. FreeTrader
    • 4 years ago
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    But I find myself going in a circle instead of isolating x. Can you give me a hint?

  4. LagrangeSon678
    • 4 years ago
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    Multiply both sides by 2x+3, you should get (2x+3)y=x-1 2xy+3y=x-1 2xy+3y+1=x 2xy-x=-3y-1 x(2y-1)=-3y-1 x=(-3y-1)/(2y-1)

  5. FreeTrader
    • 4 years ago
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    Try factoring out - x instead, which will make for a positive numerator, and I like that better. Thanks for helping me get unstuck.

  6. LagrangeSon678
    • 4 years ago
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    Your welcome, how is that calc group doing?

  7. FreeTrader
    • 4 years ago
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    I never connected with anybody at my ideal time. I did finish my Calc 1 class locally, and just found out I got an A on the final.

  8. FreeTrader
    • 4 years ago
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    Thank you for remembering.

  9. LagrangeSon678
    • 4 years ago
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    Nice job:)

  10. FreeTrader
    • 4 years ago
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    I don't think I could have gotten an A at MIT, though. I am working through the OCW class on my own in prep for Calc 2 next semester. The teaching is better, the recitations are more logically connected to the future of calculus work coming in the class, and the problems are clearly better structured to teach something specific while doing the homework as a side benefit to practicing a particular kind of problem. That makes the OCW homework feel much much more rewarding.

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