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mr.luna
how do i do this. limit as x approaches infitnity of [e^(-7x)cos(x)]
the instructions say evaluate
\[\frac{\cos{x}}{e^{7x}}\]
ohhh, small number over huge number equals negative infinity right?
\[{x\to\infty} \implies e^{7x} \to \infty\] \(\cos\) is limited to 1 and -1, So I think Zero
how can there be two values on top?
I meant \(\cos\)'s Range is [-1,1]
oh, so an infintiy under that would make it go to zero, alrite got it. thanks bro