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mr.luna

  • 4 years ago

how do i do this. limit as x approaches infitnity of [e^(-7x)cos(x)]

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  1. mr.luna
    • 4 years ago
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    the instructions say evaluate

  2. Ishaan94
    • 4 years ago
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    \[\frac{\cos{x}}{e^{7x}}\]

  3. mr.luna
    • 4 years ago
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    ohhh, small number over huge number equals negative infinity right?

  4. Ishaan94
    • 4 years ago
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    \[{x\to\infty} \implies e^{7x} \to \infty\] \(\cos\) is limited to 1 and -1, So I think Zero

  5. mr.luna
    • 4 years ago
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    how can there be two values on top?

  6. Ishaan94
    • 4 years ago
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    I meant \(\cos\)'s Range is [-1,1]

  7. mr.luna
    • 4 years ago
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    oh, so an infintiy under that would make it go to zero, alrite got it. thanks bro

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