mr.luna
evaluate limit. view to see function.



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mr.luna
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typing it in. one sec

mr.luna
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lim\[x \rightarrow2^+ e^[1/(x2)]\]

mr.luna
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dw:1324017614280:dw

Zarkon
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infinity

mr.luna
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why

eseidl
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agree

Zarkon
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look at 1/(x2)
when \(x\to2^+\), \(1/(x2)\to\infty\)

Zarkon
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to abuse notation...we get \[e^\infty=\infty\]

mr.luna
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2^+ means approaching from the right? right?

Zarkon
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correct

mr.luna
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ok . thanksn