anonymous
  • anonymous
evaluate limit. view to see function.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
typing it in. one sec
anonymous
  • anonymous
lim\[x \rightarrow2^+ e^[1/(x-2)]\]
anonymous
  • anonymous
|dw:1324017614280:dw|

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Zarkon
  • Zarkon
infinity
anonymous
  • anonymous
why
anonymous
  • anonymous
agree
Zarkon
  • Zarkon
look at 1/(x-2) when \(x\to2^+\), \(1/(x-2)\to\infty\)
Zarkon
  • Zarkon
to abuse notation...we get \[e^\infty=\infty\]
anonymous
  • anonymous
2^+ means approaching from the right? right?
Zarkon
  • Zarkon
correct
anonymous
  • anonymous
ok . thanksn

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