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whatevs
 3 years ago
Best ResponseYou've already chosen the best response.0how did you solve it...i have 5 more problems like this..

whatevs
 3 years ago
Best ResponseYou've already chosen the best response.0is there a way to put it into wolfram?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.0I looked at it then I thought of a number.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Sum%5B2+n+%2B+4%2C+%7Bn%2C+4%2C+7%7D%5D

whatevs
 3 years ago
Best ResponseYou've already chosen the best response.0can you help me with these kind of problems?

whatevs
 3 years ago
Best ResponseYou've already chosen the best response.0Given the sequence 9, 12, 15, which of the following is equivalent to

mathmate
 3 years ago
Best ResponseYou've already chosen the best response.0You can split the summations, and evaluate each one separately. \[\sum_{4}^{7}2n+4 = \sum_{4}^{7}2n + \sum_{4}^{7}4\] \[= 2\sum_{4}^{7}n + 4\sum_{4}^{7} 1\] \[= 2(\sum_{1}^{7}n  \sum_{1}^{3}n ) + 4(4)\] \[= 2[ 7(7+1)/2  3(3+1)/2 ]  16\] \[= 44 + 16\] \[= 28\]
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