## anonymous 4 years ago 36^(3c)=sqrt6^(8c+6)

1. jim_thompson5910

$\Large 36^{3c} = \sqrt{6^{8c+6}}$ $\Large 36^{3c} = \left(6^{8c+6}\right)^{\frac{1}{2}}$ $\Large (6^2)^{3c} = \left(6^{8c+6}\right)^{\frac{1}{2}}$ $\Large 6^{2*3c} = 6^{\frac{1}{2}(8c+6)}$ $\Large 6^{6c} = 6^{\frac{1}{2}(8c)+\frac{1}{2}(6)}$ $\Large 6^{6c} = 6^{4c+3}$ $\Large 6c = 4c+3$ $\Large 6c-4c = 3$ $\Large 2c = 3$ $\Large c = \frac{3}{2}$

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