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 3 years ago
vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=3.75cm.
Find a. the components of the vector sum A+B;
b. the magnitude and direction of vector A+B;
c. the components of the vector difference BA;
d. the magnitude and direction of Vector B  A.
 3 years ago
vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=3.75cm. Find a. the components of the vector sum A+B; b. the magnitude and direction of vector A+B; c. the components of the vector difference BA; d. the magnitude and direction of Vector B  A.

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imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1A=<1.3,2.25> B=<4.1,3.75> just add component by component A+B=<1.3+4.1,2.253.75> <5.4,1.5> For magnitude \[\sqrt{(5.4)^2+(1.5)^2}\] for direction \[tan^{1}(1.5/5.4)\]

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0whar? we have different answers

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1let me see what you do

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0the formula to get the vector is \[vector A= \sqrt{Ax ^{2}+ Ay^2}\] and \[Vector B= \sqrt{Vx^{2} + Vy^{2}\}

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1that will find you magnitude of vector A only

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0and vector b=\[\sqrt{Bx^2+ By^2}\]

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1oh ,you will add it afterward

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0just add it? so I came up with vector A=2.6 and vector B=5.56 so vector A + vector B = 2.6 + 5.56=8.16?

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1I think you are better off adding two vector component by component and then taking mag

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0I think that part is on how to get the magnitude. right?

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0yeah so the magnitude is \[\sqrt{(5.4)^2 + (1.5)^2}\]?

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0will I do the same thing on part c and d?

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0hey, ahmm, accordingly, when u get the magnitude, the formula for xcomp. is A cos \[\Theta\] right so we need to find the angle before we get the magnitude?

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.1oh , if you are given magnitude and direction , yes

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0i dunno what to do. what will be my answer on letter b. drivin me crazy.

yajjnobee
 3 years ago
Best ResponseYou've already chosen the best response.0how can I get the value of xcomponent if the angle is not given. and it's impossible to compute the direction first because it needs the value for both x and y components
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