Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=3.75cm.
Find a. the components of the vector sum A+B;
b. the magnitude and direction of vector A+B;
c. the components of the vector difference BA;
d. the magnitude and direction of Vector B  A.
 2 years ago
 2 years ago
vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=3.75cm. Find a. the components of the vector sum A+B; b. the magnitude and direction of vector A+B; c. the components of the vector difference BA; d. the magnitude and direction of Vector B  A.
 2 years ago
 2 years ago

This Question is Closed

imranmeah91Best ResponseYou've already chosen the best response.1
A=<1.3,2.25> B=<4.1,3.75> just add component by component A+B=<1.3+4.1,2.253.75> <5.4,1.5> For magnitude \[\sqrt{(5.4)^2+(1.5)^2}\] for direction \[tan^{1}(1.5/5.4)\]
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
whar? we have different answers
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.1
let me see what you do
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
the formula to get the vector is \[vector A= \sqrt{Ax ^{2}+ Ay^2}\] and \[Vector B= \sqrt{Vx^{2} + Vy^{2}\}
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.1
that will find you magnitude of vector A only
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
and vector b=\[\sqrt{Bx^2+ By^2}\]
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.1
oh ,you will add it afterward
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
just add it? so I came up with vector A=2.6 and vector B=5.56 so vector A + vector B = 2.6 + 5.56=8.16?
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.1
I think you are better off adding two vector component by component and then taking mag
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
I think that part is on how to get the magnitude. right?
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
yeah so the magnitude is \[\sqrt{(5.4)^2 + (1.5)^2}\]?
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
will I do the same thing on part c and d?
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
hey, ahmm, accordingly, when u get the magnitude, the formula for xcomp. is A cos \[\Theta\] right so we need to find the angle before we get the magnitude?
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.1
oh , if you are given magnitude and direction , yes
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
i dunno what to do. what will be my answer on letter b. drivin me crazy.
 2 years ago

yajjnobeeBest ResponseYou've already chosen the best response.0
how can I get the value of xcomponent if the angle is not given. and it's impossible to compute the direction first because it needs the value for both x and y components
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.