Here's the question you clicked on:
yajjnobee
vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=-3.75cm. Find a. the components of the vector sum A+B; b. the magnitude and direction of vector A+B; c. the components of the vector difference B-A; d. the magnitude and direction of Vector B - A.
A=<1.3,2.25> B=<4.1,-3.75> just add component by component A+B=<1.3+4.1,2.25-3.75> <5.4,-1.5> For magnitude \[\sqrt{(5.4)^2+(1.5)^2}\] for direction \[tan^{-1}(-1.5/5.4)\]
whar? we have different answers
let me see what you do
the formula to get the vector is \[vector A= \sqrt{Ax ^{2}+ Ay^2}\] and \[Vector B= \sqrt{Vx^{2} + Vy^{2}\}
that will find you magnitude of vector A only
and vector b=\[\sqrt{Bx^2+ By^2}\]
oh ,you will add it afterward
just add it? so I came up with vector A=2.6 and vector B=5.56 so vector A + vector B = 2.6 + 5.56=8.16?
I think you are better off adding two vector component by component and then taking mag
I think that part is on how to get the magnitude. right?
yeah so the magnitude is \[\sqrt{(5.4)^2 + (-1.5)^2}\]?
will I do the same thing on part c and d?
hey, ahmm, accordingly, when u get the magnitude, the formula for x-comp. is A cos \[\Theta\] right so we need to find the angle before we get the magnitude?
oh , if you are given magnitude and direction , yes
i dunno what to do. what will be my answer on letter b. drivin me crazy.
how can I get the value of x-component if the angle is not given. and it's impossible to compute the direction first because it needs the value for both x and y components