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kap

  • 3 years ago

Hi, i'm trying to solve this integral on this site : http://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx. The first question of Example 2: sin(1-x)(2-cos(1-x))^4 dx and i substituted u=2-cos(1-x). So i solved for du= sin(1-x)dx but the author of the tutorial says it is du=-sin(1-x)dx. Since the derivative of cosx is -sinx then the two negatives become positive. Need some explanation why he still mainstains the negative infront of the sin. thanks

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  1. anilorap
    • 3 years ago
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    when u take the derivative of 2-cos(1-x)= -(-sin)(1-x)(-1) derivative of the inside too derivative of (1-x)

  2. keira_lee
    • 3 years ago
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    that's because the negative come from differentiate of ( 1- x ) that is -1

  3. pokemon23
    • 3 years ago
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    Today's my birthday :)

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