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himanshuxain
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Divide 40 kg mass into 4 piece such that you can weigh from 1 to 40 kg from those 4 masses
 2 years ago
 2 years ago
himanshuxain Group Title
Divide 40 kg mass into 4 piece such that you can weigh from 1 to 40 kg from those 4 masses
 2 years ago
 2 years ago

This Question is Closed

vishal_kothari Group TitleBest ResponseYou've already chosen the best response.8
what's the right answer?
 2 years ago

himanshuxain Group TitleBest ResponseYou've already chosen the best response.1
ans to nahi pata to he post kara he lekin 1,2,19,18 nahi he
 2 years ago

vishal_kothari Group TitleBest ResponseYou've already chosen the best response.8
ho bhi nahi sakta?
 2 years ago

hei Group TitleBest ResponseYou've already chosen the best response.0
?? right or wrong?
 2 years ago

vishal_kothari Group TitleBest ResponseYou've already chosen the best response.8
it's wrong..
 2 years ago

hei Group TitleBest ResponseYou've already chosen the best response.0
i am not really understand wat the question want >.>
 2 years ago

vishal_kothari Group TitleBest ResponseYou've already chosen the best response.8
himanshu explain the question..
 2 years ago

himanshuxain Group TitleBest ResponseYou've already chosen the best response.1
yaar 40kg ka weight ko 4 piece me torna he jisse 1kg se 40 kg ke sabhi mass 1 ya 1 se jada piece ka use karke sabhe ko weigh karna he
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
hmm don't think this is right either.
 2 years ago

abayomi Group TitleBest ResponseYou've already chosen the best response.0
i assure u it is. the problem is an old one from Bachet's 'Problems plaisants et delectables'
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
well then tell me how with this combination u can get a weight of 2,5,7,8....... ?
 2 years ago

abayomi Group TitleBest ResponseYou've already chosen the best response.0
you have a point there, the version i remember did not place a restriction of 4 weights to the solution.
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
ya i guess this restriction is just the problem here
 2 years ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
You can weigh a 2 by putting a three on one side, and a one on the other. Ditto for 5 (9 vs 3+1)
 2 years ago

Diarmuid_Wrenne Group TitleBest ResponseYou've already chosen the best response.2
It's an old problem from pre revolution France. The conventional way of thinking was that the mass being weighed on the balance had to be measured with a number of the weights on the opposite side. The solution here is to realise that you can also add weights to the side being weighed. So 1 is weighed conventionally but 2 is weighed with a 3 on one side and a 1 being added to the side being weighed, etc 1, 1 2, 3, 1 3, 3 4,3,1 5,9,3,1 6,9,3 7,9,1,3 8,9,1 9,9
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
1,3,9,27....is right
 2 years ago
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