Here's the question you clicked on:
himanshuxain
Divide 40 kg mass into 4 piece such that you can weigh from 1 to 40 kg from those 4 masses
what's the right answer?
ans to nahi pata to he post kara he lekin 1,2,19,18 nahi he
ho bhi nahi sakta?
i am not really understand wat the question want >.>
himanshu explain the question..
yaar 40kg ka weight ko 4 piece me torna he jisse 1kg se 40 kg ke sabhi mass 1 ya 1 se jada piece ka use karke sabhe ko weigh karna he
hmm don't think this is right either.
i assure u it is. the problem is an old one from Bachet's 'Problems plaisants et delectables'
well then tell me how with this combination u can get a weight of 2,5,7,8....... ?
you have a point there, the version i remember did not place a restriction of 4 weights to the solution.
ya i guess this restriction is just the problem here
You can weigh a 2 by putting a three on one side, and a one on the other. Ditto for 5 (9 vs 3+1)
It's an old problem from pre revolution France. The conventional way of thinking was that the mass being weighed on the balance had to be measured with a number of the weights on the opposite side. The solution here is to realise that you can also add weights to the side being weighed. So 1 is weighed conventionally but 2 is weighed with a 3 on one side and a 1 being added to the side being weighed, etc 1, 1 2, 3, -1 3, 3 4,3,1 5,9,-3,-1 6,9,-3 7,9,1,-3 8,9,-1 9,9