Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

ALGEBRA in Calculus proof... Can you help me understand the basis for bringing delta x upstairs into only the numerator in this step of a problem?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

\[1/\Delta x * (\Delta u)v - u(\Delta v)/(v + \Delta v)v\] \[((\Delta u / \Delta x)v - u(\Delta v/\Delta x))/(v + \Delta v)v\]
This is from Lecture Session 10 of MIT OCW Math 18.01 Scholar - Single Variable Calculus.
The lecture and lecture notes show what I typed above. I don't understand why the Delta x would not have to be multiplied against the (v + Delta v)v term in the denominator.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

How does the Delta x term get into the numerator of the numerator?
\[{{1\overΔx}(Δu)v−u(Δv)\over(v+Δv)v} \to {{Δu \overΔx}v−u{Δv \overΔx}\over(v+Δv)v}\]is the step?
Almost. The 1/Delta x is a separate fraction. It started out as simply Delta x under everything else.
And then ended up as you have on the right hand side.
see attached for more clarity. It's near the bottom third of the page...
oh this is simple: multiply out the bottom by delta x then divide the top and bottom by delta x much easier when I can see it!
or divide top and bottom of \[{1\over \Delta x}\] by \[\Delta x\]you get\[{{1\over \Delta x}\over1}{(\Delta u)v-u (\Delta v)\over(v+\Delta v)v}\]
I need to go to Algebra Tricks Boot Camp. Thanks.
I still think that is really funky. I will need to do some test problems to convince my rock-like brain this works just like you show it does.

Not the answer you are looking for?

Search for more explanations.

Ask your own question