A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Add and simplify if possible:
anonymous
 5 years ago
Add and simplify if possible:

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3 \over x5 \] + \[5 \over x ^{2}25\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do u know what's special about x^2 25?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's something called "the difference of 2 perfect squares".

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all that means is x^2  a perfect square=(x+the square root)(xthe square root)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so x^225 becomes (x+5)(x5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k, so now u havedw:1324334896764:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply the 3/x5 by (x+5)/(x+5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that gives us a common denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So \[3x + 20 \over (x+5) (x5)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so busy concentrating on my drawing that I couldn't see what you posted :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@meow  see the lcm question
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.