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FreeTrader

  • 3 years ago

Given the expression 3sin(2x-pi), how would I go about determining the phase angle?

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  1. elica85
    • 3 years ago
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    does it have to do with physics-oscillation?

  2. FreeTrader
    • 3 years ago
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    This is a homework problem, in which I am given a list of parameters including phase angle, and told to determine those parameters, then sketch the graph of the expression.

  3. FreeTrader
    • 3 years ago
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    Phase angle was not covered in lecture or recitation. As best I can recall, I have never been asked to determine phase angle of a sine function, even back in trig, and do not know how to go about that. Any help would be appreciated.

  4. elica85
    • 3 years ago
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    hm the only time i had to solve for phase angle was in physics finding it by using the equation \[x(t)=Acos(\omega(t)+\phi)\] which will give you the position of a mass attached to a spring at time t. however, it turns into a sine function when determining the velocity by differentiating so \[x'(t)=-A \omega \sin(\omega(t)+\phi)\]

  5. elica85
    • 3 years ago
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    A was amplitude (max displacement)

  6. MissPacGirl
    • 3 years ago
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    didu guys get a web reloading notice?

  7. elica85
    • 3 years ago
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    yes

  8. FreeTrader
    • 3 years ago
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    I believe the amplitude is 3, the period is pi, and the phase shift would be pi/2 to the right. The solution sheet for this problem says the phase angle is pi/2, so maybe phase angle is synonymous with phase shift.

  9. elica85
    • 3 years ago
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    that's what i was thinking except i thought pi would be the phase angle. how did you get pi/2?

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