## anonymous 4 years ago Given the expression 3sin(2x-pi), how would I go about determining the phase angle?

1. anonymous

does it have to do with physics-oscillation?

2. anonymous

This is a homework problem, in which I am given a list of parameters including phase angle, and told to determine those parameters, then sketch the graph of the expression.

3. anonymous

Phase angle was not covered in lecture or recitation. As best I can recall, I have never been asked to determine phase angle of a sine function, even back in trig, and do not know how to go about that. Any help would be appreciated.

4. anonymous

hm the only time i had to solve for phase angle was in physics finding it by using the equation $x(t)=Acos(\omega(t)+\phi)$ which will give you the position of a mass attached to a spring at time t. however, it turns into a sine function when determining the velocity by differentiating so $x'(t)=-A \omega \sin(\omega(t)+\phi)$

5. anonymous

A was amplitude (max displacement)

6. anonymous

7. anonymous

yes

8. anonymous

I believe the amplitude is 3, the period is pi, and the phase shift would be pi/2 to the right. The solution sheet for this problem says the phase angle is pi/2, so maybe phase angle is synonymous with phase shift.

9. anonymous

that's what i was thinking except i thought pi would be the phase angle. how did you get pi/2?