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The volume of a sphere radius r increases at 12pi cm^3/minute by inflation. What is the rate of growth of its surface area?

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Noo..? This is a maths question.
This is what's called related rate problem
rate of change.

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Other answers:

volume of sphere = 4/3 Pi r^3
I know, i got stuck, there's not enough info :/
first find the derivative of V first
I already know. I got stuck in dA/dt = 8pi3*dr/dt There's not enough info.
your missing the rate that the radius is increasing.
I found that the radius is sqrt(3)
how did you come about that? there is no volume given
i mean the derivative of volume
write equation relating volume to surface area v= 4/3 Pi r^3 S= 4 Pi r^2 v= s/3 r dv/ds= 1/3r dv= 1/3 r ds
We would still need r though right? or do you think they want the answer in terms of r?
boo i already gave you a medal lolol
Mimi skipped basic math and went straight to calculus.
Shut up Hero, people don't need to know that i dont know basic maths. v= s/3r? where did that come from?
*minor correction v= 4/3 Pi r^3 S= 4 Pi r^2 v= (s r)/3 dv/ds= r/3 dv= r/3 ds (12*3 Pi)/r= ds

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