Mimi_x3
  • Mimi_x3
The volume of a sphere radius r increases at 12pi cm^3/minute by inflation. What is the rate of growth of its surface area?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Mimi_x3
  • Mimi_x3
Noo..? This is a maths question.
anonymous
  • anonymous
This is what's called related rate problem
Mimi_x3
  • Mimi_x3
rate of change.

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More answers

anonymous
  • anonymous
volume of sphere = 4/3 Pi r^3
anonymous
  • anonymous
|dw:1324353965977:dw|
Mimi_x3
  • Mimi_x3
I know, i got stuck, there's not enough info :/
anonymous
  • anonymous
first find the derivative of V first
Mimi_x3
  • Mimi_x3
I already know. I got stuck in dA/dt = 8pi3*dr/dt There's not enough info.
anonymous
  • anonymous
your missing the rate that the radius is increasing.
anonymous
  • anonymous
youre*
Mimi_x3
  • Mimi_x3
I found that the radius is sqrt(3)
anonymous
  • anonymous
how did you come about that? there is no volume given
anonymous
  • anonymous
i mean the derivative of volume
anonymous
  • anonymous
write equation relating volume to surface area v= 4/3 Pi r^3 S= 4 Pi r^2 v= s/3 r dv/ds= 1/3r dv= 1/3 r ds
anonymous
  • anonymous
We would still need r though right? or do you think they want the answer in terms of r?
anonymous
  • anonymous
boo i already gave you a medal lolol
Hero
  • Hero
Mimi skipped basic math and went straight to calculus.
Mimi_x3
  • Mimi_x3
Shut up Hero, people don't need to know that i dont know basic maths. v= s/3r? where did that come from?
anonymous
  • anonymous
*minor correction v= 4/3 Pi r^3 S= 4 Pi r^2 v= (s r)/3 dv/ds= r/3 dv= r/3 ds (12*3 Pi)/r= ds
Mimi_x3
  • Mimi_x3
ty.

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