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First, find two vectors in the plane PQR: PQ=<02,1(4),23>=<2,3,1> PR=<12,1(4),13>=<1,5,2> PQxPR is the normal to the plane PQR: i j k 2 3 1 1 5 2 =<1,3,7> The plane is defined by the normal passing through one of the three points, we can choose (1,1,1) for convenience: 1(x1) 3(y1) 7(z1)=0 which simplifies to x+3y+7z11=0 as the equation of the required plane. Check that all points PQR lie in the plane.
 2 years ago
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