At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
quick analysis shows there's no need for the density
is it cylindrical or conical?
says cylindrical right up there :-P
how could a cylinder have different cross sectional area? :-p
I guess A1 = A2 then :-D
|dw:1324391145896:dw| This is the cylinder right?!
it's not illustrated inn the problem, but that is a cylinder indeed!
why u posted 2 same questions? and it's physics isn't it?
it's actually physics.... so yeah :-D
im stuck on the very first problem lol
If you could, do try to keep physics questions in the physics group. You can use chat to get people to come to that group if you're not getting traction there :)
You need to say that you use the 'dimensional analysis' .... It's just about getting the units of time (the unknown) equal to the units on the right side. So all the 'meters' on the right hand side should add up to 0. This is a tool to find a relation that COULD fullfill the requirements. The problem consists of density, h, A1, A2 and gravity g. Now you just write your solution in the form: t = rho^a*h^b*A1^c*A2^d*g^e You see that the only time dependent variable is g. So g should be (m/s^2) to the power of -1/2 to obtain seconds. The other variables like meter work in the same way, try to get rid of all of them by making a couple of easy assumptions
I don't know how to make valid assumptions though :(