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jesusfreak
Group Title
Expand the series and evaluate:
∑ {5(on top), k=1(on bottom), k^3 on the right side}
 2 years ago
 2 years ago
jesusfreak Group Title
Expand the series and evaluate: ∑ {5(on top), k=1(on bottom), k^3 on the right side}
 2 years ago
 2 years ago

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jesusfreak Group TitleBest ResponseYou've already chosen the best response.0
\[\sum_{k=1}^{5} k^3\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
i think its just the square of k^1
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
\[\sum k=\frac{n(n+1)}{2}\] \[\sum k^3=\left(\frac{n(n+1)}{2}\right)^2\] rings a bell to me
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
It's always a good idea to list out the elements of series this small:\[1^3+2^3+3^3+4^3+5^3.\]
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
Just to get a feel for it, you feel me!? ^^
 2 years ago

jesusfreak Group TitleBest ResponseYou've already chosen the best response.0
Yeah, thanks. So would it be 1, 8, 27, 64, 125?
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
Don't forget that it's a summation! :P
 2 years ago

jesusfreak Group TitleBest ResponseYou've already chosen the best response.0
What do you mean?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
you have to add them...
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.2
Deriving this proof is a good excercise, there are many ways actually, but I like way of differentiating and then substituting .. probably that's how euler did it!
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
euler plagarized the chinese :P
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.2
^^ lol, how do you know ? :P
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
past life regression :)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
if we take the derivative of this life ....
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.2
You were there when Euler did it? ... omG! :D
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.4
yep, just call me JC Superstar yay!!
 2 years ago

jesusfreak Group TitleBest ResponseYou've already chosen the best response.0
Okay, I hope you two know that that wasn't very helpful. I am just wondering how to solve this. Across, what do you mean by a summation?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
ADD them up! that is what summation means
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
I said it above but nobody cared...
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
\[1^3+2^3+3^3+4^3+5^3=?\]
 2 years ago
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