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jesusfreak
 3 years ago
Expand the series and evaluate:
∑ {5(on top), k=1(on bottom), k^3 on the right side}
jesusfreak
 3 years ago
Expand the series and evaluate: ∑ {5(on top), k=1(on bottom), k^3 on the right side}

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jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^{5} k^3\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4i think its just the square of k^1

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4\[\sum k=\frac{n(n+1)}{2}\] \[\sum k^3=\left(\frac{n(n+1)}{2}\right)^2\] rings a bell to me

across
 3 years ago
Best ResponseYou've already chosen the best response.0It's always a good idea to list out the elements of series this small:\[1^3+2^3+3^3+4^3+5^3.\]

across
 3 years ago
Best ResponseYou've already chosen the best response.0Just to get a feel for it, you feel me!? ^^

jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, thanks. So would it be 1, 8, 27, 64, 125?

across
 3 years ago
Best ResponseYou've already chosen the best response.0Don't forget that it's a summation! :P

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0you have to add them...

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.2Deriving this proof is a good excercise, there are many ways actually, but I like way of differentiating and then substituting .. probably that's how euler did it!

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4euler plagarized the chinese :P

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.2^^ lol, how do you know ? :P

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4past life regression :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4if we take the derivative of this life ....

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.2You were there when Euler did it? ... omG! :D

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.4yep, just call me JC Superstar yay!!

jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, I hope you two know that that wasn't very helpful. I am just wondering how to solve this. Across, what do you mean by a summation?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0ADD them up! that is what summation means

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0I said it above but nobody cared...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0\[1^3+2^3+3^3+4^3+5^3=?\]
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