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henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1That there is a mirrorplane/point/line... The equation is similarly shaped on both sides of this mirror

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0but they use it like "Deduce the value of f'(1) f'(2) using symmetry." and give you a graph of

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.01 sec let me get the graph

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1symmetry axis = x=0 f`(1) = f`(1) f'(2) =f'(2) Does that help?

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0so is it just flipping the graph?

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0but how would flipping a graph give you a value?

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1Because the value of the point f'(1) has a relation to the point f'(1)..

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1Though you need to know the value of f'(x) in point 1

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0so would you just add a negative sign in front of it cause it is flipped?

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1yes, that is what a mirrorplane does.

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1srry, mirrorline in 2D ;P

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0cause in my teachers book, it says "f'(x) = f'(x)"

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, that's what I said, right?

DoomDude
 3 years ago
Best ResponseYou've already chosen the best response.0ya.. so is it that simple, just a negative sign?
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