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but they use it like "Deduce the value of f'(1) f'(2) using symmetry." and give you a graph of

1 sec let me get the graph

f(x) = x^2

symmetry axis = x=0
f`(1) = -f`(-1)
f'(2) =-f'(-2)
Does that help?

so is it just flipping the graph?

More or less. yep

but how would flipping a graph give you a value?

Because the value of the point f'(1) has a relation to the point f'(-1)..

Though you need to know the value of f'(x) in point -1

so would you just add a negative sign in front of it cause it is flipped?

yes, that is what a mirrorplane does.

srry, mirrorline in 2D ;P

cause in my teachers book, it says "f'(-x) = -f'(x)"

Yes, that's what I said, right?

ya.. so is it that simple, just a negative sign?

indeed

ok, thanks