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henkjanBest ResponseYou've already chosen the best response.1
That there is a mirrorplane/point/line... The equation is similarly shaped on both sides of this mirror
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
but they use it like "Deduce the value of f'(1) f'(2) using symmetry." and give you a graph of
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
1 sec let me get the graph
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
symmetry axis = x=0 f`(1) = f`(1) f'(2) =f'(2) Does that help?
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
so is it just flipping the graph?
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
but how would flipping a graph give you a value?
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
Because the value of the point f'(1) has a relation to the point f'(1)..
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
Though you need to know the value of f'(x) in point 1
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
so would you just add a negative sign in front of it cause it is flipped?
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
yes, that is what a mirrorplane does.
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
srry, mirrorline in 2D ;P
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
cause in my teachers book, it says "f'(x) = f'(x)"
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
Yes, that's what I said, right?
 2 years ago

DoomDudeBest ResponseYou've already chosen the best response.0
ya.. so is it that simple, just a negative sign?
 2 years ago
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