dawn354215
solve 2(3m)+15=6m4(m20)



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henkjan
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2(3m) = 6 + 2m

henkjan
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4(m20) = 4m + 80

henkjan
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use both and substitute:
6+2m +15 = 6m4m+80

henkjan
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hmm.. Now we end up with 2m on both sides.... this equation is erroneous

dawn354215
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yea that is where i got confused

jimmyrep
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there are no solutions

henkjan
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indeed

dawn354215
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ok thanks i thought so just needed a little reassurance

jimmyrep
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yw