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jesusfreak

  • 3 years ago

Expand the series and evaluate: Enter your answer as the following example: -1-2-3-4-5-6=-21 sum_(k=5)^10(-5k)

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  1. amistre64
    • 3 years ago
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    whats your best effort give us?

  2. amistre64
    • 3 years ago
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    seeing this done a few times should give you an idea that we can build upon

  3. jesusfreak
    • 3 years ago
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    Ok @amistre64, please leave me alone

  4. amistre64
    • 3 years ago
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    ok, but good luck with it all :)

  5. jesusfreak
    • 3 years ago
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    Can someone help me please?

  6. amistre64
    • 3 years ago
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    im willing to help, but ....

  7. jesusfreak
    • 3 years ago
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    But what?

  8. amistre64
    • 3 years ago
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    you said you dont want me to help you

  9. jesusfreak
    • 3 years ago
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    I want help I just don't want to be criticized

  10. amistre64
    • 3 years ago
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    noones criticizing you. I just need to know how much you know on this subject.

  11. amistre64
    • 3 years ago
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    does the notation make sense for starters.

  12. amistre64
    • 3 years ago
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    \[\sum_{k=5}^{10}\]is a good place to start

  13. jesusfreak
    • 3 years ago
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    I know nothing

  14. amistre64
    • 3 years ago
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    then this might take a bit. It is simple enough tho. the symbol: \(\sum\) is a greek letter for "S" and indicated that we are going to be adding up stuff

  15. amistre64
    • 3 years ago
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    the number on the bottom tells us where we start at; and the number on top tells us where we end at: in this case we start with k=5 and end with k=10

  16. jesusfreak
    • 3 years ago
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    ok

  17. amistre64
    • 3 years ago
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    i like to write it out to begin with like this: k : rule ------- 5 : -5k = -5(5) = -25 6 : -5k = -5(6) = -30 7 : -5k = -5(7) = -35 8 : -5k = -5(8) = -40 9 : -5k = -5(9) = -45 10: -5k = -5(10)= -50 does this make sense so far?

  18. amistre64
    • 3 years ago
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    \[\sum_{First}^{Last}(rule)\] using the rule, and stepping thru the numbers from first to last, we can generate all the numbers that are needed to be added up.

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