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moneybirdBest ResponseYou've already chosen the best response.3
A regular polygon, with 49 sides, is inscribed in a circle. How many triangles with vertices that are vertices of the polygon have the centre of the circle in their interior?
 2 years ago

moneybirdBest ResponseYou've already chosen the best response.3
I have not gotten the solution yet
 2 years ago

asnaseerBest ResponseYou've already chosen the best response.1
For an 'n' sided polygon, if we label each vertex of the polygon from 1 to n and consider the triangle from the center of the circle to the first two vertices, we get this diagram: dw:1324760887506:dw Now consider some vertex labelled 'i'. We need to pick the position of this vertex such that it lies between the projections of vertex 1 and 2 through the center of the triangle  this will ensure that a triangle drawn between vertices 1, 2 and 'i' will contain the center of the circle. This leads us to this inequality:\[ \begin{align} \pi+\frac{2\pi}{n}&>&\frac{2\pi}{n}*(i1)&>\pi\\ \therefore n+2&>&2(i1)&>n\\ \therefore \frac{n+2}{2}&>&i1&>\frac{n}{2}\\ \therefore \frac{n+4}{2}&>&i&>\frac{n+2}{2} \end{align}\]so, for a polygon with 49 sides we get:\[26.5>i>25.5\]and since 'i' has to be an integer, there is only only one solution which is \(i=26\). So for the edge between vertices 1 and 2, we can construct just one triangle to vertex 26 which contains the center of the circle. Since this polygon has 49 edges, we can therefore form 49 such triangles. So I think the answer is 49.
 2 years ago

StomBest ResponseYou've already chosen the best response.0
i think i have got the solution to this, it comes out to be a series, for a polygon with n sides, if n is odd then ans is n1/2 for even n ans is n4/2 i got that by anlysing the cases of hexagon, septagon and octagon, and seeing the pattern
 2 years ago
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