A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
The Steamboat aloftser in Yellowstone National Park, Wyoming is capable of shooting its hot water up from the ground with a speed of 48.0 m/s. How high can this geyser shoot? (HINT: USE KINEMATIC EQUATIONS)
anonymous
 4 years ago
The Steamboat aloftser in Yellowstone National Park, Wyoming is capable of shooting its hot water up from the ground with a speed of 48.0 m/s. How high can this geyser shoot? (HINT: USE KINEMATIC EQUATIONS)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use energy conservation kinetic energy is converted into potential here. Ekin = 1/2mv^2 Epot =m*g*h 1/2V^2 = g*h

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im confused, can you explain it more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You conserve energy here..... the kinetic energy in the start is 1/2*m*v^2 ALL this energy is converted to potential energy. The potential energy at the end is given as: m*g*h You know they are equal, so we can use an equation to calculate the height h. m*g*h = m*1/2*V^2 We see that we can take m out: g*h = 1/2 V^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So you cant do anything other than that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, you can... but this is the easiest way to do it. You can also solve by using s = 1/2*a*t^2.. a = g = 9.81 m/s2 t = v/g = 48/9.81 s = 1/2 * a * (v/g)^2 = 9.81*(48/9.81)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But it boils down into the same equation as: s = h = 1/2 * g * (v/g)^2 = 1/2 *V^2/g
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.