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oh sorry yea its suppose to be J is the midpoint of KL

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|dw:1324417943491:dw|

so i wud just use the points to find L?

That's right;
given\[J:(-8,7),\]\[K:(3,4),\]can you find the equation of the line?

Remember the point-slope formula\[y=m(x-x_1)+y_1,\]where\[m=\frac{y_2-y_1}{x_2-x_1}.\]

you can yea, but im not sure what formula to use

ohh

First find m, and then find the equation. :) Tell me what you get.

i got -3/11 for M

That's correct;\[m=-\frac{3}{11}.\]

so thats your cordinates right?

(We're almost done, too!)

i got -0.86 which i think is way off?..

For the equation of the line, I got\[y=-\frac{3}{11}x+\frac{53}{11}.\]Do you agree with this?

yea im sure you did it right im just not sure what u did?...(this is why geometry confuses me)

I only did one thing: I found the equation of the line formed by the points J and K.

o i got that equation but when i simplified it i got -0.86 for some reason

After distributing, you should get a term having an x in it:|dw:1324419228233:dw|

oh i changed -3/11 to a fraction thats why i got confused i think

i mean a decimal not a fraction

you simplify it more, and you get\[y=-\frac{3}{11}x+\frac{53}{11}\] :)

The final step is at hand! Are you ready for it?

Yes Ma'am

Now, we know that the x-distance from point J to point K is 11, right?
J:(-8*,7)
K:(3*,4)
8+3=11

If we go 11 units to the left of -8, what do we get?

-19?

y=m(x−x1)+y1, that formula?

This one\[y=-\frac{3}{11}x+\frac{53}{11}.\]:)

i got -4/11 ? is that right?

\[-\frac{3}{11}\cdot(-19)+\frac{53}{11}=\frac{57}{11}+\frac{53}{11}=\frac{110}{11}=10\]

ohh i added -57 to 53

Yeah, the signs can become a pain at times. ^^

haha yeah thank you for your help

thank you soo much for walking through it and helping me i really appreciate it

you're most welcome!

(:

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