A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1thats what i dont know.

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1there is also an equation here..

Tomas.A
 2 years ago
Best ResponseYou've already chosen the best response.0type in whole problem question

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W  R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross  sectional area as shown.

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1Do you know any air resistance coefficient... Normally it's given as: Fdrag = A*C Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant. Further on, do you know the area (A in previous formula) of mr Bronco?

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1so what do i need to multiply or divide? or subtract or +

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1I don't see how "Air resistance (R) varies with seed and cross  sectional area as shown. " Because it isn't shown

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1it's just a picture of a guy falling trying to skydive. with an arrow pointing down.

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1i can take a picture and somehow attach it here..

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1so do u know how to calculate it now?

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1If there is no air resistance (R=0) and he will just jump straight down, his accelerations are: a(y) = 0 a(x) = 0 a(z) = g = 9.81 m/s (if z points down is positive, note SI units)

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1coordinate system.. x and y are the horizontal components, z is vertical

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1ok, so the acceleration is 0?

henkjan
 2 years ago
Best ResponseYou've already chosen the best response.1in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)

justinee
 2 years ago
Best ResponseYou've already chosen the best response.1i hatteeeeeee physics.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.