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justineeBest ResponseYou've already chosen the best response.1
thats what i dont know.
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
there is also an equation here..
 2 years ago

Tomas.ABest ResponseYou've already chosen the best response.0
type in whole problem question
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W  R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross  sectional area as shown.
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
Do you know any air resistance coefficient... Normally it's given as: Fdrag = A*C Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant. Further on, do you know the area (A in previous formula) of mr Bronco?
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
so what do i need to multiply or divide? or subtract or +
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
I don't see how "Air resistance (R) varies with seed and cross  sectional area as shown. " Because it isn't shown
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
it's just a picture of a guy falling trying to skydive. with an arrow pointing down.
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
i can take a picture and somehow attach it here..
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
so do u know how to calculate it now?
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
If there is no air resistance (R=0) and he will just jump straight down, his accelerations are: a(y) = 0 a(x) = 0 a(z) = g = 9.81 m/s (if z points down is positive, note SI units)
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
coordinate system.. x and y are the horizontal components, z is vertical
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
ok, so the acceleration is 0?
 2 years ago

henkjanBest ResponseYou've already chosen the best response.1
in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)
 2 years ago

justineeBest ResponseYou've already chosen the best response.1
i hatteeeeeee physics.
 2 years ago
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