justinee
i neeed need in my hmwk! :/
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justinee
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with*
henkjan
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What's wrong?
Tomas.A
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u didn't post question
justinee
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|dw:1324427060151:dw|
Tomas.A
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whats R? whats W?
justinee
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thats what i dont know.
justinee
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there is also an equation here..
Tomas.A
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type in whole problem question
justinee
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Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W - R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross - sectional area as shown.
Tomas.A
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what is Bronco?
henkjan
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a dude
henkjan
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Do you know any air resistance coefficient...
Normally it's given as: Fdrag = A*C
Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant.
Further on, do you know the area (A in previous formula) of mr Bronco?
justinee
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so what do i need to multiply or divide? or subtract or +
henkjan
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I don't see how "Air resistance (R) varies with seed and cross - sectional area as shown. "
Because it isn't shown
justinee
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it's just a picture of a guy falling trying to skydive. with an arrow pointing down.
justinee
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i can take a picture and somehow attach it here..
henkjan
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If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)
justinee
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so do u know how to calculate it now?
henkjan
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If there is no air resistance (R=0) and he will just jump straight down, his accelerations are:
a(y) = 0
a(x) = 0
a(z) = g = 9.81 m/s (if z points down is positive, note SI units)
justinee
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what is (y) (x) (z)
Tomas.A
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axis of coordinates
henkjan
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coordinate system.. x and y are the horizontal components, z is vertical
justinee
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ok, so the acceleration is 0?
henkjan
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in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)
justinee
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oh okay! thanks! :)
justinee
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i hatteeeeeee physics.
henkjan
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haha. no worries