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anonymous
 5 years ago
i neeed need in my hmwk! :/
anonymous
 5 years ago
i neeed need in my hmwk! :/

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u didn't post question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1324427060151:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i dont know.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is also an equation here..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0type in whole problem question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W  R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross  sectional area as shown.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know any air resistance coefficient... Normally it's given as: Fdrag = A*C Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant. Further on, do you know the area (A in previous formula) of mr Bronco?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what do i need to multiply or divide? or subtract or +

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't see how "Air resistance (R) varies with seed and cross  sectional area as shown. " Because it isn't shown

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's just a picture of a guy falling trying to skydive. with an arrow pointing down.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can take a picture and somehow attach it here..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so do u know how to calculate it now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If there is no air resistance (R=0) and he will just jump straight down, his accelerations are: a(y) = 0 a(x) = 0 a(z) = g = 9.81 m/s (if z points down is positive, note SI units)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0coordinate system.. x and y are the horizontal components, z is vertical

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so the acceleration is 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i hatteeeeeee physics.
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