Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

henkjan Group TitleBest ResponseYou've already chosen the best response.1
What's wrong?
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
u didn't post question
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
dw:1324427060151:dw
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
whats R? whats W?
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
thats what i dont know.
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
there is also an equation here..
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
type in whole problem question
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W  R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross  sectional area as shown.
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
what is Bronco?
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
Do you know any air resistance coefficient... Normally it's given as: Fdrag = A*C Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant. Further on, do you know the area (A in previous formula) of mr Bronco?
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
so what do i need to multiply or divide? or subtract or +
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
I don't see how "Air resistance (R) varies with seed and cross  sectional area as shown. " Because it isn't shown
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
it's just a picture of a guy falling trying to skydive. with an arrow pointing down.
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
i can take a picture and somehow attach it here..
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
so do u know how to calculate it now?
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
If there is no air resistance (R=0) and he will just jump straight down, his accelerations are: a(y) = 0 a(x) = 0 a(z) = g = 9.81 m/s (if z points down is positive, note SI units)
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
what is (y) (x) (z)
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
axis of coordinates
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
coordinate system.. x and y are the horizontal components, z is vertical
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
ok, so the acceleration is 0?
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
oh okay! thanks! :)
 2 years ago

justinee Group TitleBest ResponseYou've already chosen the best response.1
i hatteeeeeee physics.
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.1
haha. no worries
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.