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justinee

  • 2 years ago

i neeed need in my hmwk! :/

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  1. justinee
    • 2 years ago
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    with*

  2. henkjan
    • 2 years ago
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    What's wrong?

  3. Tomas.A
    • 2 years ago
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    u didn't post question

  4. justinee
    • 2 years ago
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    |dw:1324427060151:dw|

  5. Tomas.A
    • 2 years ago
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    whats R? whats W?

  6. justinee
    • 2 years ago
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    thats what i dont know.

  7. justinee
    • 2 years ago
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    there is also an equation here..

  8. Tomas.A
    • 2 years ago
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    type in whole problem question

  9. justinee
    • 2 years ago
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    Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W - R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross - sectional area as shown.

  10. Tomas.A
    • 2 years ago
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    what is Bronco?

  11. henkjan
    • 2 years ago
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    a dude

  12. henkjan
    • 2 years ago
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    Do you know any air resistance coefficient... Normally it's given as: Fdrag = A*C Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant. Further on, do you know the area (A in previous formula) of mr Bronco?

  13. justinee
    • 2 years ago
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    so what do i need to multiply or divide? or subtract or +

  14. henkjan
    • 2 years ago
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    I don't see how "Air resistance (R) varies with seed and cross - sectional area as shown. " Because it isn't shown

  15. justinee
    • 2 years ago
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    it's just a picture of a guy falling trying to skydive. with an arrow pointing down.

  16. justinee
    • 2 years ago
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    i can take a picture and somehow attach it here..

  17. henkjan
    • 2 years ago
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    If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)

  18. justinee
    • 2 years ago
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    so do u know how to calculate it now?

  19. henkjan
    • 2 years ago
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    If there is no air resistance (R=0) and he will just jump straight down, his accelerations are: a(y) = 0 a(x) = 0 a(z) = g = 9.81 m/s (if z points down is positive, note SI units)

  20. justinee
    • 2 years ago
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    what is (y) (x) (z)

  21. Tomas.A
    • 2 years ago
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    axis of coordinates

  22. henkjan
    • 2 years ago
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    coordinate system.. x and y are the horizontal components, z is vertical

  23. justinee
    • 2 years ago
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    ok, so the acceleration is 0?

  24. henkjan
    • 2 years ago
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    in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)

  25. justinee
    • 2 years ago
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    oh okay! thanks! :)

  26. justinee
    • 2 years ago
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    i hatteeeeeee physics.

  27. henkjan
    • 2 years ago
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    haha. no worries

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