- anonymous

i neeed need in my hmwk! :/

- chestercat

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- anonymous

with*

- anonymous

What's wrong?

- anonymous

u didn't post question

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## More answers

- anonymous

|dw:1324427060151:dw|

- anonymous

whats R? whats W?

- anonymous

thats what i dont know.

- anonymous

there is also an equation here..

- anonymous

type in whole problem question

- anonymous

Using \[a = \left(\begin{matrix}Fnet \\ m\end{matrix}\right) = \left(\begin{matrix}W - R \\ m\end{matrix}\right)\] find Bronco's acceleration at each position. You need to know that his mass is 100 kg, so his weight is a constant 1000 N. Air resistance (R) varies with seed and cross - sectional area as shown.

- anonymous

what is Bronco?

- anonymous

a dude

- anonymous

Do you know any air resistance coefficient...
Normally it's given as: Fdrag = A*C
Where A is area of the person perpendicular to it's direction and C is some sort of air drag constant.
Further on, do you know the area (A in previous formula) of mr Bronco?

- anonymous

so what do i need to multiply or divide? or subtract or +

- anonymous

I don't see how "Air resistance (R) varies with seed and cross - sectional area as shown. "
Because it isn't shown

- anonymous

it's just a picture of a guy falling trying to skydive. with an arrow pointing down.

- anonymous

i can take a picture and somehow attach it here..

- anonymous

If R=0, as you show in your figure, and straight down (as in figure) ... the only acceleration he gets is gravitational acceleration (g=9.81 m/s^2)

- anonymous

so do u know how to calculate it now?

- anonymous

If there is no air resistance (R=0) and he will just jump straight down, his accelerations are:
a(y) = 0
a(x) = 0
a(z) = g = 9.81 m/s (if z points down is positive, note SI units)

- anonymous

what is (y) (x) (z)

- anonymous

axis of coordinates

- anonymous

coordinate system.. x and y are the horizontal components, z is vertical

- anonymous

ok, so the acceleration is 0?

- anonymous

in horizontal direction, yes... it's 9.81 m/s2 in vertical direction (down)

- anonymous

oh okay! thanks! :)

- anonymous

i hatteeeeeee physics.

- anonymous

haha. no worries

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