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milliex51
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How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
 2 years ago
 2 years ago
milliex51 Group Title
How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
 2 years ago
 2 years ago

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milliex51 Group TitleBest ResponseYou've already chosen the best response.0
dw:1324423827086:dw
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.0
F = m*a F = 2 N m = 6 kg??? (not really clear what the cart exactly is from your drawing) F = m*a a = F/m a = 2/6 = 1/3 m/s2 (a deceleration, maybe you want to add a minus sign in the force of the resistance)
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
The answer is 2.9 m/s ^2 [fwd] in the back of my book.. but
 2 years ago

henkjan Group TitleBest ResponseYou've already chosen the best response.0
than i misinterpretted your picture, let me guess again :P
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
and I found the formula for no friction only: T = m1a a = m2g/(m1 + m2)
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
F=MA. Which means summation of forces is equal to mass times acceleration. There are two different blocks so there are two different free body diagrams. Block of 4 KG. There's a force normal and a force gravity and a force friction and a force tension. Block of 2 KG. There's a force tension and a force gravity only. So for the 2nd block FtFg= MA. > Ft2.0(9.8)=2.0(a) > 4.0a+2.02.0(9.8)=2.0a solve for a 1st block. FtFf=MA. > Ft2.0 = 4.0(a) Ft=4.0a+2.0
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
m=4kg from her pic
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
ohhh.. I think I'm getting it. o.o
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
May I ask why ft  Fg = ma?
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
sometimes I don't get these formulas >_<"
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
Look at the block. Look at what's "touching it" And then there are also 4non contact forces that can act upon the block. Force gravity, electric force, magnetism force, and I forget the last one
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
yes, tension force? normal force? applied force?
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
So for the 2.0 KG block only a rope is touching the block. Which is Force Tension (Ft) and a noncontact force force gravity (Fg)
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
equtoion of motion for 2.5kg is 2.5g  T = 2.5a ......................................4kg is T  2 = 4.5a solving this sytem will give you the reqd acceleration
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
because total force=ma and the total force is force of the object pulling on one end of the string minus the friction force (because it is acting in the opposite direction).
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
yup, I see it! :)
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
ohhhhhhhh.
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
thank you!!
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
No problem. I hope you understand the problem now ^_^. Remember to draw free body diagrams of the entire system and remember contact forces and noncontact forces
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
yeah I will! Wait, what do you mean by contact and noncontact forces? Like tension force, gravity force, normal force, applied force... etc?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
gravity force is noncontact because it touches nothing in order to impart a force on it.
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
Contact is forces that are literally touching the object you are drawing the free body diagram for. Non contact forces are "invisible" forces. There are only 4 forces that are "invisible" but I think the only one you'll ever face in basic physics is "Force Gravity". There are two more for more advanced physics "Electrical and Magnetism". Contact forces can be : Force friction (From a surface) or force tension (from a rope) force spring (from a spring) and much more
 2 years ago

milliex51 Group TitleBest ResponseYou've already chosen the best response.0
ohhhh, i see, i see. THANK YOU S O MUCH!! :D
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
you sure its 2.9 m/s/s for acceleration
 2 years ago

hyunaelee Group TitleBest ResponseYou've already chosen the best response.2
No problems. Good luck ^_^ and hope you do well.
 2 years ago
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