A community for students.
Here's the question you clicked on:
 0 viewing
 3 years ago
How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
 3 years ago
How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.

This Question is Closed

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1324423827086:dw

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.0F = m*a F = 2 N m = 6 kg??? (not really clear what the cart exactly is from your drawing) F = m*a a = F/m a = 2/6 = 1/3 m/s2 (a deceleration, maybe you want to add a minus sign in the force of the resistance)

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0The answer is 2.9 m/s ^2 [fwd] in the back of my book.. but

henkjan
 3 years ago
Best ResponseYou've already chosen the best response.0than i misinterpretted your picture, let me guess again :P

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0and I found the formula for no friction only: T = m1a a = m2g/(m1 + m2)

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2F=MA. Which means summation of forces is equal to mass times acceleration. There are two different blocks so there are two different free body diagrams. Block of 4 KG. There's a force normal and a force gravity and a force friction and a force tension. Block of 2 KG. There's a force tension and a force gravity only. So for the 2nd block FtFg= MA. > Ft2.0(9.8)=2.0(a) > 4.0a+2.02.0(9.8)=2.0a solve for a 1st block. FtFf=MA. > Ft2.0 = 4.0(a) Ft=4.0a+2.0

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh.. I think I'm getting it. o.o

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0May I ask why ft  Fg = ma?

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0sometimes I don't get these formulas >_<"

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2Look at the block. Look at what's "touching it" And then there are also 4non contact forces that can act upon the block. Force gravity, electric force, magnetism force, and I forget the last one

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0yes, tension force? normal force? applied force?

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2So for the 2.0 KG block only a rope is touching the block. Which is Force Tension (Ft) and a noncontact force force gravity (Fg)

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0equtoion of motion for 2.5kg is 2.5g  T = 2.5a ......................................4kg is T  2 = 4.5a solving this sytem will give you the reqd acceleration

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0because total force=ma and the total force is force of the object pulling on one end of the string minus the friction force (because it is acting in the opposite direction).

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2No problem. I hope you understand the problem now ^_^. Remember to draw free body diagrams of the entire system and remember contact forces and noncontact forces

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0yeah I will! Wait, what do you mean by contact and noncontact forces? Like tension force, gravity force, normal force, applied force... etc?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0gravity force is noncontact because it touches nothing in order to impart a force on it.

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2Contact is forces that are literally touching the object you are drawing the free body diagram for. Non contact forces are "invisible" forces. There are only 4 forces that are "invisible" but I think the only one you'll ever face in basic physics is "Force Gravity". There are two more for more advanced physics "Electrical and Magnetism". Contact forces can be : Force friction (From a surface) or force tension (from a rope) force spring (from a spring) and much more

milliex51
 3 years ago
Best ResponseYou've already chosen the best response.0ohhhh, i see, i see. THANK YOU S O MUCH!! :D

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0you sure its 2.9 m/s/s for acceleration

hyunaelee
 3 years ago
Best ResponseYou've already chosen the best response.2No problems. Good luck ^_^ and hope you do well.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.