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log(x+2)+log(x-1) = log ((x+2)(x-1))
maybe that helps ;P

So
(x+2)(x-1) = 10^1
x^2+x-2= 10
x^2+x-12 = 0
Solve for x and find x = -4 and x = 3

but it's equal to one??, in the first line you have the equation equal to 10

isn't the b 10?

no, the b is equal to the right side in this equation log ((x+2)(x-1)) =1 ...... so it's 1

okay

so if the equation was equal to 2 the b would be 10^2?

log(x)+log(y) = log(x*y)
if log(a)=b
then 10^b = a
only 2 rules I used

yes, indeed than it would be a = 10^2 = 100

:) alright, the answer at the back of the text is just 3, why isn't the -4 acceptable?

oh okay, thank you very much