I'm not good with logs, can someone help me?
log(x+2)+log(x-1)=1

I'm not good with logs, can someone help me?
log(x+2)+log(x-1)=1

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log(x+2)+log(x-1) = log ((x+2)(x-1))
maybe that helps ;P

So
(x+2)(x-1) = 10^1
x^2+x-2= 10
x^2+x-12 = 0
Solve for x and find x = -4 and x = 3

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