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anonymous
 5 years ago
HEEEELP!! How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
anonymous
 5 years ago
HEEEELP!! How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1324432388146:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart. It first asks what the acceleration will be with no friction is acting on a cart and my formula is: T = m1a m2a = m2g  T T = m2g  m2a m1a+ m2a = m2g a = m2g / (m1 + m2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the answer for my current problem stated above is 2.9 m/s^2... and I don't know how to solve it D;

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a=F/m F=driving forceresistant force what's the driving force in this case?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0driving force? It.. It doesn't say.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i'm just asking you to think about it. it will help you in solving problems in the future. what force is causing the system to move?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this moving to the left?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so no it's not the tension force. it's the force from the hanging mass

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gravity causes the masses to move

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh, i see it. 'Cause when the hanging mass falls the cart moves.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so \[driving force=m _{hanging}*g\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now the resistant force is already given in the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how? And is your equation the same as: a = m2g / (m1 + m2)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are you using for m2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you said how the resistant force is already given in the problem how?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok then yes, it will end up as that equation you have but i will break it down a=F/m resistant force = 2N F=2g2N =19.6N2N back to acceleration... a=F/mass of the system = (19.6N2N)/(2kg+4kg)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get 2N as the resistant force? o.O 'cause the answer in the back of the text is 2.9 m/s^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, actually different than yours but i'm confident in what i put up there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know a way in which I can use my formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh but do you know how to answer the problem with my formula? ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tension cancels out for this system which is why i didn't use it in any of my equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your formula seems a little off but i will double check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0break down the system in 2 parts. hanging mass will be labeled 1. \[m _{1}gT _{1}=m _{1}a\] ^^^derived from F=ma solve for T \[T _{1}=m _{1}(ga)\] for second part... \[T _{2}m _{2}g=m _{2}a\] solve for T... \[T _{2}=m _{2}(g+a)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what you have to calculate a would work if there was no friction but since there is, the best way to do it is the way i did it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh, cos that formula I showed you was for no friction & I thought maybe to switch a few places would be okay.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well then, thank you so much elica for putting up with me!! Thank you!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw, why is it: F=2g2N? Why is it 2g?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after you calculate 2g (2kg*9.8m/s^2) it will equal to 19.6N. the unit N=kg*m/s^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just remember you can't add or subtract unless they have the same units

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh, so it's like m2g?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh, okay. Thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so F = m2g  frictional resistance? (what's the variable for it?)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in this case, frictional force is denoted as \[F _{k}=\mu mg\] k for kinetic friction and the ulooking sign is the friction coefficient which is usually given in a problem. in this problem, the Fk was already solved (2N)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhh, I'm familiar with that! Oh, thank you!
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