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HEEEELP!! How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
 2 years ago
 2 years ago
HEEEELP!! How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart.
 2 years ago
 2 years ago

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milliex51Best ResponseYou've already chosen the best response.0
dw:1324432388146:dw
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
How do I calculate the acceleration of the cart shown, given the following assumption: A frictional resistance of magnitude 2.0 N is acting on the cart. It first asks what the acceleration will be with no friction is acting on a cart and my formula is: T = m1a m2a = m2g  T T = m2g  m2a m1a+ m2a = m2g a = m2g / (m1 + m2)
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
and the answer for my current problem stated above is 2.9 m/s^2... and I don't know how to solve it D;
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
a=F/m F=driving forceresistant force what's the driving force in this case?
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
driving force? It.. It doesn't say.
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
well i'm just asking you to think about it. it will help you in solving problems in the future. what force is causing the system to move?
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
is this moving to the left?
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
ok, so no it's not the tension force. it's the force from the hanging mass
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
gravity causes the masses to move
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohh, i see it. 'Cause when the hanging mass falls the cart moves.
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
so \[driving force=m _{hanging}*g\]
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
now the resistant force is already given in the problem
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
how? And is your equation the same as: a = m2g / (m1 + m2)?
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
what are you using for m2?
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
and you said how the resistant force is already given in the problem how?
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
ok then yes, it will end up as that equation you have but i will break it down a=F/m resistant force = 2N F=2g2N =19.6N2N back to acceleration... a=F/mass of the system = (19.6N2N)/(2kg+4kg)
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
how did you get 2N as the resistant force? o.O 'cause the answer in the back of the text is 2.9 m/s^2
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
oops, actually different than yours but i'm confident in what i put up there
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
do you know a way in which I can use my formula?
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohhh but do you know how to answer the problem with my formula? ...
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
tension cancels out for this system which is why i didn't use it in any of my equations
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
your formula seems a little off but i will double check
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
break down the system in 2 parts. hanging mass will be labeled 1. \[m _{1}gT _{1}=m _{1}a\] ^^^derived from F=ma solve for T \[T _{1}=m _{1}(ga)\] for second part... \[T _{2}m _{2}g=m _{2}a\] solve for T... \[T _{2}=m _{2}(g+a)\]
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
so what you have to calculate a would work if there was no friction but since there is, the best way to do it is the way i did it
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohh, cos that formula I showed you was for no friction & I thought maybe to switch a few places would be okay.
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
Well then, thank you so much elica for putting up with me!! Thank you!!
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
btw, why is it: F=2g2N? Why is it 2g?
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
after you calculate 2g (2kg*9.8m/s^2) it will equal to 19.6N. the unit N=kg*m/s^2
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
just remember you can't add or subtract unless they have the same units
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohhh, so it's like m2g?
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohh, okay. Thank you!
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
so F = m2g  frictional resistance? (what's the variable for it?)
 2 years ago

elica85Best ResponseYou've already chosen the best response.1
in this case, frictional force is denoted as \[F _{k}=\mu mg\] k for kinetic friction and the ulooking sign is the friction coefficient which is usually given in a problem. in this problem, the Fk was already solved (2N)
 2 years ago

milliex51Best ResponseYou've already chosen the best response.0
ohhhh, I'm familiar with that! Oh, thank you!
 2 years ago
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