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davian

  • 3 years ago

Find the measure of angle CDE<---help please

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  1. davian
    • 3 years ago
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  2. ricnus
    • 3 years ago
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    Well straight up I can tell you the answer is 65 for CDE, I used simultaneous equations to find this You know that the addition of all angles is 180, so then you know that the remaining interior angles must equal to 130 because 180 take the already known angle, 50, is 130, so that means that your first equation is going to be \[x+y=130\] Your second equation is going to be 180, because that is the angle of the straight line take away the equation in CDE equals y \[180-(2x-15)=y\] You can now view it as; \[x+y = 130, 2 x+y = 195\] \[x=130-y, 2(130-y)+y=195\] \[260-2y+y=195\] \[65-y=o\] \[y=65\] \[x+(65)=130\] \[x=130-65\] \[x=65\]

  3. indianalexander
    • 3 years ago
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    180- (50+x) + (2x-15) = 180 -50 -x +2x -15 =0 x=75 therefore, angle cde =135

  4. indianalexander
    • 3 years ago
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    x=65 sorry

  5. indianalexander
    • 3 years ago
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    addition mistake :p cde= 115

  6. ricnus
    • 3 years ago
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    No, sorry the answer is 115 because 65 is the interior angles, so 180-65=115

  7. davian
    • 3 years ago
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    @ricnus thats so much that was alot of work and @indianaalexander thank you to

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